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B
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Difficulty:
35%
(medium)
Question Stats:
73% (01:55) correct
28%
(02:08)
wrong
based on 80
sessions
History
Date
Time
Result
Not Attempted Yet
Bob spots his friend 500 meters ahead of him while driving along the same road in the same direction. Bob drives at a speed of 18 km/h, while his friend drives at 12 km/h. How far will the friend travel before Bob catches up?
A. 0.5 km
B. 1 km
C. 1.5 km
D. 2 km
E. 2.5 km
A. 0.5 km
B. 1 km
C. 1.5 km
D. 2 km
E. 2.5 km
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M47-29
14 Feb 2026, 08:30
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Bunuel
GMAT Club Official Solution:
Key step: use relative speed because the gap closes at (18 - 12) km/h.
Initial gap = 500 m = 0.5 km
Time to catch = 0.5/(18 - 12) = 0.5/6 = 1/12 hour
Friend’s distance in that time = 12*(1/12) = 1 km
Answer: B.
General Discussion
06 Feb 2026, 11:51
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Bunuel
A friend is 500 m ahead of Bob.
The speed of Bob is 18 kmph, and the speed of Friend is 12 kmph.
Both going in Same direction = 18-12 = 6 kmph. = 6 *(5/18) = (5/3) metre per seconds.
Time to catch his friend = 500 / (5/3)
= 300 seconds = 5 minutes.
Distance travelled by Friend in 12 kmph for 5 minutes.
12 km in 60 minutes.
Then, for 5 minutes , they travelled 1 km.
Option B
