Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
79% (01:56) correct
21%
(02:09)
wrong
based on 106
sessions
History
Date
Time
Result
Not Attempted Yet
John usually walks to work at a certain speed, but today, due to walking at only 3/5 of his usual speed, he arrives 10 minutes late. How long would John have taken to reach his destination if he had walked at his usual speed?
A. 10 minutes
B. 15 minutes
C. 20 minutes
D. 25 minutes
E. 30 minutes
A. 10 minutes
B. 15 minutes
C. 20 minutes
D. 25 minutes
E. 30 minutes
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
M47-31
14 Feb 2026, 10:15
Kudos
Bookmarks
Bunuel
GMAT Club Official Solution:
Let John’s usual time be t minutes. Since time is inversely proportional to speed for the same distance, walking at 3/5 of his usual speed makes his time t/(3/5) = 5/3 * t.
5/3 * t = t + 10
2/3 * t = 10
t = 15
Answer: B.
General Discussion
06 Feb 2026, 10:41
Kudos
Bookmarks
This is a classic speed-distance-time problem, and once you set it up correctly, the math is very clean.
Step 1: Define variables.
Let John's usual speed be s, and let the usual time to reach work be t. Then the distance to work is d = s * t.
Step 2: Set up the equation for today.
Today he walks at 3/5 of his usual speed, so his speed is (3/5)s. Since the distance doesn't change:
d = (3/5)s * t_new
Since d = s * t, we get:
s * t = (3/5)s * t_new
t_new = (5/3) * t
Step 3: Use the "10 minutes late" information.
The extra time is:
t_new - t = (5/3)t - t = (2/3)t = 10 minutes
Solving: t = 10 * (3/2) = 15 minutes.
Answer: B (15 minutes)
Common trap: Some students set up the ratio backwards and get 25 minutes. Remember — slower speed means more time, so t_new must be greater than t. The multiplier for time is the inverse of the speed fraction: speed is 3/5 of normal, so time is 5/3 of normal.
Takeaway: Whenever a speed-distance-time problem gives you a fraction of the usual speed and the resulting time difference, set up the equation (new time) - (old time) = difference. The distance cancels out, and you're left with a simple equation.
Step 1: Define variables.
Let John's usual speed be s, and let the usual time to reach work be t. Then the distance to work is d = s * t.
Step 2: Set up the equation for today.
Today he walks at 3/5 of his usual speed, so his speed is (3/5)s. Since the distance doesn't change:
d = (3/5)s * t_new
Since d = s * t, we get:
s * t = (3/5)s * t_new
t_new = (5/3) * t
Step 3: Use the "10 minutes late" information.
The extra time is:
t_new - t = (5/3)t - t = (2/3)t = 10 minutes
Solving: t = 10 * (3/2) = 15 minutes.
Answer: B (15 minutes)
Common trap: Some students set up the ratio backwards and get 25 minutes. Remember — slower speed means more time, so t_new must be greater than t. The multiplier for time is the inverse of the speed fraction: speed is 3/5 of normal, so time is 5/3 of normal.
Takeaway: Whenever a speed-distance-time problem gives you a fraction of the usual speed and the resulting time difference, set up the equation (new time) - (old time) = difference. The distance cancels out, and you're left with a simple equation.
