kevincan
At a fast-food restaurant , employees earn x dollars per hour for each of the first 35 hours worked in a week, plus 3x/2 dollars per hour for each additional hour worked. Last week, the youngest employee at this restaurant worked 4 more hours than the oldest, earning 5x dollars more. If they earned a total of $2,201 last week, how much did the youngest employee earn last week?
A. $1,116
B. $1,147
C. $1,178
D. $1,209
E. $1,240
Good question.
If they both worked \(t\) hours where \(t > 35\) then difference in pay would be:
\(35x + (t+4-35)1.5x -( 35x + (t-35)1.5x = 6x\)... As the pay difference is \(5x\) this case is not possible.
If they both worked less than \(35\) hours even after including overtime , then :
\(( t+4)x -tx= 4x\)... As the pay difference is \(5x\) this case is also not possible.
If the younger one worked exactly \(4\) hours over \(35\), well as older didn't,then difference in pay would be:
\(35x + 4*1.5x - 35x = 6x\)... As the pay difference is \(5x\) this case is also not possible.
Hence it must be that, \(t+4>35\) well as \(t < 35. \)\(35x + (t+4-35)1.5x -( tx ) =5x \)
\(t =33\).. Older person worked for \(33\) hours
Thus youngest one worked \(33+4 = 37\) hours
\(35x + 2*1.5x + 33x = 2201\) ---Total pay given
\(x = 31 \)... this is normal pay per hour.
Hence youngest's earnings \(35 *x + 2 * 1.5x = 38x= 38*31 = 1178 \)
Ans C
Hope it helped.