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B
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Difficulty:
75%
(hard)
Question Stats:
70% (03:20) correct
30%
(03:08)
wrong
based on 33
sessions
History
Date
Time
Result
Not Attempted Yet
Parisa traveled from her home to the gym by the same route on two consecutive days. On the first day, she jogged 3/5 of the distance at 12 km/h and walked the remaining distance at 6 km/h. On the second day, she jogged at 12 km/h for 3/5 of the time and walked at 6 km/h for the remaining time. If the total time on the first day was 3 minutes longer than on the second day, what is the distance from her home to the gym?
A. 2 km
B. 4 km
C. 6 km
D. 8 km
E. 12 km
A. 2 km
B. 4 km
C. 6 km
D. 8 km
E. 12 km
05 Mar 2026, 22:56
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kevincan
Let’s assume the distance to be as d.
Case 1: (3/5) of the distance at 12 kmph.
Time t1 = ?
12 = (3/5)d /t1
t1 = d/20
(2/5) of the distance at 6 kmph.
t2 = (d/15)
Total time = (d/20)+(d/15) = (7d/60)
Case 2:
Let’s find the total distance d.
d = 12*(3/5)t + 6*(2/5)t
Solving, we get
t = 5d/48
The difference of times from case 1 is 3 minutes more than time from case 2.
(7d/60) - (5d/48) = (3/60)
Solving we get, d=4 km
Option B
07 Mar 2026, 07:00
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Key concept being tested: Distance-Speed-Time with mixed conditions — specifically the difference between dividing a distance into fractions vs. dividing time into fractions. This is one of the most common traps in GMAT speed questions.
The trap: Most students set up both days identically using distance fractions. Day 2 says she jogged "3/5 of the time" — not 3/5 of the distance. The moment you miss that word, both equations collapse into the same thing and you can't find a unique answer.
Step 1 — Set up Day 1 (fraction of distance).
Let d = total distance (km). She jogs 3d/5 at 12 km/h and walks 2d/5 at 6 km/h.
Time1 = (3d/5)/12 + (2d/5)/6 = d/20 + d/15
Finding common denominator: d/20 + d/15 = 3d/60 + 4d/60 = 7d/60
Step 2 — Set up Day 2 (fraction of time). This is where it changes.
Let total time on Day 2 = T. She jogs for 3T/5 at 12 km/h and walks for 2T/5 at 6 km/h.
Distance = 12 x (3T/5) + 6 x (2T/5) = 36T/5 + 12T/5 = 48T/5
Since this equals d: T = 5d/48
Step 3 — Use the 3-minute difference.
Day 1 took 3 minutes longer than Day 2. Convert 3 minutes to hours: 3/60 = 1/20.
7d/60 - 5d/48 = 1/20
Find common denominator (240):
(28d - 25d)/240 = 1/20
3d/240 = 1/20
d = 240/(20 x 3) = 4 km
Answer: B
Takeaway: Any time a problem switches between "fraction of distance" and "fraction of time" across two scenarios, write those words explicitly before setting up your equation — that single swap changes the entire structure of the algebra.
— Kavya | 725 (99th percentile), GMAT Focus Edition
The trap: Most students set up both days identically using distance fractions. Day 2 says she jogged "3/5 of the time" — not 3/5 of the distance. The moment you miss that word, both equations collapse into the same thing and you can't find a unique answer.
Step 1 — Set up Day 1 (fraction of distance).
Let d = total distance (km). She jogs 3d/5 at 12 km/h and walks 2d/5 at 6 km/h.
Time1 = (3d/5)/12 + (2d/5)/6 = d/20 + d/15
Finding common denominator: d/20 + d/15 = 3d/60 + 4d/60 = 7d/60
Step 2 — Set up Day 2 (fraction of time). This is where it changes.
Let total time on Day 2 = T. She jogs for 3T/5 at 12 km/h and walks for 2T/5 at 6 km/h.
Distance = 12 x (3T/5) + 6 x (2T/5) = 36T/5 + 12T/5 = 48T/5
Since this equals d: T = 5d/48
Step 3 — Use the 3-minute difference.
Day 1 took 3 minutes longer than Day 2. Convert 3 minutes to hours: 3/60 = 1/20.
7d/60 - 5d/48 = 1/20
Find common denominator (240):
(28d - 25d)/240 = 1/20
3d/240 = 1/20
d = 240/(20 x 3) = 4 km
Answer: B
Takeaway: Any time a problem switches between "fraction of distance" and "fraction of time" across two scenarios, write those words explicitly before setting up your equation — that single swap changes the entire structure of the algebra.
— Kavya | 725 (99th percentile), GMAT Focus Edition
