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GRE 1: Q170 V170
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The x value in the first alligation must be 21.25 and not 21.5. Kindly check it out!
tryorcry
there are two mixtures here. 1st that is formed by wine and rum containing some alcohol %age and 2nd mixting soda(0 alcohol) with mixture obtained from 1st calc.

1st mixture.
13%----x-------35%

(35-x)/(x-13) = 40/24 ( ratio of their presence in the newly formed mixture = ratio of actual weights of wine and rum )
x= 21.5

now next mixture
0%-----5%-------21.5%
SODA MIX

Presence of soda weight of soda Y
------------------ = ----------------- = ------------
mix weight of mix 64

16.5/5 = Y/64

Y= 33*64

now to get the number of bottles we must divide Y with 16

i.e, Y/16 = 13.2

So we need atleast 13.2 or more bottles of soda to ensure that alcohol is less than 5%

Hence Answer D.


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