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Daphnee
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OA:
This is the fastest and most straightforward way I could think of but please let me know if there is a better way :v

First, determine the possible combinations of three numbers that sum to 20, using an decreasing order (x≥y≥z) to avoid confusion or duplication. Then, calculate the number of permutations for each combination.
Combination (9, 9, 2) → 3 permutations (3!/2!).
Combination (9, 8, 3) → 6 permutations (3!).
Combination (9, 7, 4) → 6 permutations (3!).
Combination (9, 6, 5) → 6 permutations (3!).
Combination (8, 8, 4) → 3 permutations (3!/2!).
Combination (8, 7, 5) → 6 permutations (3!).
Combination (8, 6, 6) → 3 permutations (3!/2!).
Combination (7, 7, 6) → 3 permutations (3!/2!).
Total outcomes: 36 ways.
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