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Let’s suppose the shipment contains n panettone at a cost of c each, and that fraction f were sold before Christmas at a fixed price of p each
We want to find (1-f)/f

Revenue before Xmas was 100% of cost of shipment :

fnp = nc

Total revenue was 36% greater than cost of shipment :

fnp + 3(1-f)np/5 = 1.36fnp

f + 3(1 -f)/5 = 34f/25
25f + 15(1-f) = 34f
15=24f
f = 5/8
1-f = 3/8
(1-f)/f = 3/5

kevincan
A supermarket chain received a shipment of panettones and recouped 100% of the cost of the shipment before Christmas by selling a fraction of them at a fixed price. After Christmas, it sold each of the remaining panettones at a price 40% lower than the pre-Christmas price. If the total revenue from the sale of the panettones was 36% greater than the cost of the shipment, the number of panettones sold after Christmas was what fraction of the number sold before Christmas?

(A) \(\frac{3}{8}\)

(B) \(\frac{3}{5}\)

(C) \(\frac{5}{8}\)

(D) \(\frac{2}{3}\)

(E) \(\frac{4}{5}\)
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Express solution :

F + 0.6(1 - f) = 1.36f

0.6(1-f) = 0.36f

(1 -f)/f = 36/60= 3/5
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