Last visit was: 05 Sep 2026, 20:37 It is currently 05 Sep 2026, 20:37
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
placeatex
Joined: 27 Jan 2026
Last visit: 03 Sep 2026
Posts: 5
Own Kudos:
10
 [8]
Given Kudos: 15
Location: India
Products:
Posts: 5
Kudos: 10
 [8]
2
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
User avatar
placeatex
Joined: 27 Jan 2026
Last visit: 03 Sep 2026
Posts: 5
Own Kudos:
Given Kudos: 15
Location: India
Products:
Posts: 5
Kudos: 10
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
justdivyanshii
Joined: 03 Jan 2025
Last visit: 28 Aug 2026
Posts: 6
Own Kudos:
1
 [1]
Given Kudos: 56
Posts: 6
Kudos: 1
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
AdarshSambare
Joined: 29 Jan 2022
Last visit: 02 Sep 2026
Posts: 314
Own Kudos:
Given Kudos: 137
Concentration: General Management, Sustainability
GPA: 2
WE:Engineering (Manufacturing)
Posts: 314
Kudos: 164
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let
A = 1 + sqrt(2) + sqrt(3) and B = sqrt(2) + sqrt(3).

=> A^2 − B^2 = (A − B)(A + B)
= (1 + sqrt(2) + sqrt(3) − sqrt(2) − sqrt(3)) × (1 + sqrt(2) + sqrt(3) + sqrt(2) + sqrt(3))
= 1 × (1 + 2sqrt(2) + 2sqrt(3))
= 1 + 2sqrt(2) + 2sqrt(3).
Option: D
User avatar
HarshavardhanR
Joined: 16 Mar 2023
Last visit: 05 Sep 2026
Posts: 649
Own Kudos:
758
 [1]
Given Kudos: 99
Status:Independent GMAT Tutor
Affiliations: Ex - Director, Subject Matter Expertise at e-GMAT
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 649
Kudos: 758
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post


---
Harsha
Attachment:
GMAT-Club-Forum-ury2i06n.png
GMAT-Club-Forum-ury2i06n.png [ 33.79 KiB | Viewed 668 times ]
User avatar
kevincan
User avatar
GMAT Instructor
Joined: 04 Jul 2006
Last visit: 05 Sep 2026
Posts: 2,478
Own Kudos:
Given Kudos: 451
GMAT 1: 790 Q51 V51
GRE 1: Q170 V170
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GMAT 1: 790 Q51 V51
GRE 1: Q170 V170
Posts: 2,478
Kudos: 4,918
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Think of sqrt 2 + sqrt 3 as x

(1 + x)^2 - x^2 = (1 + 2x + x^2) - x^2= 1 + 2x
User avatar
TheAdmissionHub
Joined: 11 May 2026
Last visit: 05 Sep 2026
Posts: 127
Own Kudos:
116
 [1]
Given Kudos: 1
GMAT 1: 740 Q51 V39
GMAT 1: 740 Q51 V39
Posts: 127
Kudos: 116
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let x be \(\sqrt{2}+ \sqrt{3}\)

We can rewrite the expression as:

\((1+x)^2-x^2=\)

\(=x^2+1+2x-x^2=\)

\(=1 + 2x=\)

\(=1 + 2( \sqrt{2}+ \sqrt{3})=\)

\(=1 + 2\sqrt{2}+ 2\sqrt{3})\)


Answer: D
User avatar
MartyMurray
Joined: 11 Aug 2023
Last visit: 05 Sep 2026
Posts: 2,159
Own Kudos:
Given Kudos: 244
GMAT 1: 800 Q51 V51
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GMAT 1: 800 Q51 V51
Posts: 2,159
Kudos: 8,180
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Which of the following is equal to \((1 + \sqrt{2} + \sqrt{3})^2 - (\sqrt{2}+\sqrt{3})^2\)?

This question could be done via expansion of the two squared expressions. At the same time, there's a much faster way: using the difference of squares pattern that commonly appears in GMAT Problem Solving questions.

Considering \((1 + \sqrt{2} + \sqrt{3})^2 - (\sqrt{2}+\sqrt{3})^2\) carefully, we can see that it's a difference of squares, in the form \(a^2 - b^2\).

Accordingly, we can use the fact that \(a^2 - b^2 = (a + b)(a - b)\) to answer this question quickly.

\((1 + \sqrt{2} + \sqrt{3})^2 - (\sqrt{2}+\sqrt{3})^2\)

\(((1 + \sqrt{2} + \sqrt{3}) + (\sqrt{2}+\sqrt{3}))((1 + \sqrt{2} + \sqrt{3}) - (\sqrt{2}+\sqrt{3}))\)

\((1 + 2\sqrt{2} + 2\sqrt{3})(1)\)

\(1 + 2\sqrt{2} + 2\sqrt{3}\)

A. \(1\)

B. \(2\)

C. \(-1 + 2\sqrt{2}\)

D. \(1 + 2\sqrt{2} + 2\sqrt{3}\)

E. \(2 + 2\sqrt{2} + 2\sqrt{3}\)


Correct answer: D
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 05 Sep 2026
Posts: 16,643
Own Kudos:
Given Kudos: 491
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,643
Kudos: 81,184
Kudos
Add Kudos
Bookmarks
Bookmark this Post
placeatex
This is a question from official mock #3, and the first time I have come across (a+b+c)^2 being tested in the GMAT during my (albeit fairly brief) studies

placeatex
It is actually testing difference of squares: \(a^2 - b^2 = (a+b)(a-b)\) and that is tested very often in GMAT. You do not need to use \((a+b+c)^2\) here and if you did, it would take too much time. It is a bit cumbersome for GMAT though I still recommend memorizing it (in case nothing else comes to mind). Do note though that you can simply do the multiplication (a+b+c)(a+b+c) to get the answer but chances of a making a careless calculation mistake increase exponentially in that case.
Moderator:
Math Expert
113155 posts