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For how many integers \(k\) does the equation \(x^2+kx=750\) have two integer roots whose sum is greater than 5?

The value of \(k\) will depend on the values of the roots. So, we can answer the question by determining how many possible pairs of roots are such that the roots multiply to -750 and their sum is greater than 5.

\(750 = 1 × 2 × 3 × 5^3\)

We can now use the prime factors in an organized way to find the pairs of factors whose sum is greater than \(5\):

-1, 750

-2, 375

-3, 250

-5, 150

-6, 125

-10, 75

-15, 30

If we shift any other prime factors to the negative number, the positive will not be more than 5 greater than the negative. So, we're done.

Total: 7

(A) 6
(B) 7
(C) 10
(D) 12
(E) 14


Correct answer: B
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