Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0301:30 AM EDT
-02:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT 
Sep 0712:30 AM EDT
-01:30 AM EDT
Tejas studied hard but kept repeating the same mistakes. After 3 attempts at 645, a focused 4-week strategy helped him identify and fix what was holding him back—leading to a 695 with just 12–15 hours of study per week.- Sep 07
10:00 AM PDT
-11:00 AM PDT
A complete walkthrough of GMAT Club’s free 12-week GMAT study plan: what you study each week, how progress and goals are tracked, how the error log works, and how your practice unlocks paid tools at no cost. - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway - Sep 09
10:00 AM PDT
-11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application... 
Sep 1008:00 PM PDT
-09:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
23 Aug 2026, 04:10
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
54% (02:31) correct
46%
(02:44)
wrong
based on 39
sessions
History
Date
Time
Result
Not Attempted Yet
A food-truck owner restocks supplies before a weekend festival. The owner can buy items priced at $7, $9, $20, $35, and $60. If the owner buys exactly $200 worth of these items, then which of the following could be the total number of items purchased?
I. 26
II. 27
III. 28
A. Only I
B. Only II
C. Only III
D. Only I and III
E. I, II, and III
I. 26
II. 27
III. 28
A. Only I
B. Only II
C. Only III
D. Only I and III
E. I, II, and III
23 Aug 2026, 06:58
Kudos
Bookmarks
A food-truck owner restocks supplies before a weekend festival. The owner can buy items priced at $7, $9, $20, $35, and $60. If the owner buys exactly $200 worth of these items, then which of the following could be the total number of items purchased?
I. 26
II. 27
III. 28
A. Only I
B. Only II
C. Only III
D. Only I and III
E. I, II, and III
Take $7 as the starting price for each item.
If all n items cost $7, the total is 7n. We then check whether the remaining amount needed to reach $200 can be obtained by replacing some $7 items with more expensive ones.
Compared with a $7 item:
$9 adds $2
$20 adds $13
$35 adds $28
$60 adds $53
I. 26 items
26 * $7 = $182.
So we need an extra $18 to get to $200.
We can get $18 by replacing nine $7 items with nine $9 items:
9 * $2 = $18.
So 26 items is possible: 17 items priced at $7 and 9 items priced at $9, for a total of 26 items costing exactly $200.
II. 27 items
27 * $7 = $189.
So we need an extra $11 to get to $200.
Also, some items must be $7 items, since even 27 items at $9 each would cost 27 * $9 = $243, already more than $200.
Now, every time we replace a $7 item with a $9 item, we add $2. Replacing it with a $20, $35, or $60 item adds at least $13, which is already more than the $11 we need.
So the only usable increase is $2, and no number of $2 increases can total $11.
Thus, 27 items is not possible.
III. 28 items
28 * $7 = $196.
So we need an extra $4 to get to $200.
Replace two $7 items with two $9 items:
2 * $2 = $4.
So 28 items is possible: 26 items priced at $7 and 2 items priced at $9, for a total of 28 items costing exactly $200.
Answer: D.
I. 26
II. 27
III. 28
A. Only I
B. Only II
C. Only III
D. Only I and III
E. I, II, and III
Take $7 as the starting price for each item.
If all n items cost $7, the total is 7n. We then check whether the remaining amount needed to reach $200 can be obtained by replacing some $7 items with more expensive ones.
Compared with a $7 item:
$9 adds $2
$20 adds $13
$35 adds $28
$60 adds $53
I. 26 items
26 * $7 = $182.
So we need an extra $18 to get to $200.
We can get $18 by replacing nine $7 items with nine $9 items:
9 * $2 = $18.
So 26 items is possible: 17 items priced at $7 and 9 items priced at $9, for a total of 26 items costing exactly $200.
II. 27 items
27 * $7 = $189.
So we need an extra $11 to get to $200.
Also, some items must be $7 items, since even 27 items at $9 each would cost 27 * $9 = $243, already more than $200.
Now, every time we replace a $7 item with a $9 item, we add $2. Replacing it with a $20, $35, or $60 item adds at least $13, which is already more than the $11 we need.
So the only usable increase is $2, and no number of $2 increases can total $11.
Thus, 27 items is not possible.
III. 28 items
28 * $7 = $196.
So we need an extra $4 to get to $200.
Replace two $7 items with two $9 items:
2 * $2 = $4.
So 28 items is possible: 26 items priced at $7 and 2 items priced at $9, for a total of 28 items costing exactly $200.
Answer: D.
23 Aug 2026, 09:24
Kudos
Bookmarks
can this trick work where in you must buy even number of odd priced itemi can directly slect even options ?
Bunuel
