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Let Rex's income = 100, then:

Rex = 100
Paul = 60
Quentin = 48
Sam = 36

Rex gives 60 dollars to sam, so now sam has 96 dollars
Rex gives 40 dollars to Quentin, so now Quentin has 88 dollars

The fraction Q/S = 11/12
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Option A

P = 0.6R
Q = 0.8P = 0.8*0.6R = 0.48R
S = 0.6P = 0.6*0.6R = 0.36R
New Income:
Q = 0.48R + 0.4R = 0.88R
S = 0.36R + 0.6R = 0.96R

Q/S = 0.88/0.96 = 11/12
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hsk
Paul's income is 40% less than Rex's income, Quentin's income is 20% less than Paul's income, and Sam's income is 40% less than Paul's income. If Rex gave 60% of his income to Sam and 40% of his income to Quentin, Quentin's new income would be what fraction of Sam's new income?

(A) 11/12
(B) 13/17
(C) 13/19
(D) 12/19
(E) 11/19

From the information given in the question, we can create the following equations in which P = Paul’s income, R = Rex’s income, Q = Quentin’s income, and S = Sam’s income.

P = 0.6R, or R = P/0.6

Q = 0.8P

S = 0.6P

Now we have all variables in terms of P.

Let’s choose a convenient value for P. If P = 30, we have:

R = P/0.6 = 30/0.6 = 50

Q = 0.8 x 30 = 24

S = 0.6 x 30 = 18

Since Rex gives 60% of his income to Sam and 40% of his income to Quentin, he gives 0.6 x 50 = 30 dollars to Sam and the remaining 20 dollars to Quentin. Thus, Sam now has 18 + 30 = 48 dollars and Quentin now has 24 + 20 = 44 dollars.

Therefore, Quentin’s new income is 44/48 = 11/12 of Sam’s new income.

Answer: A
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f Rex's income is 100 you can deduce the following :

R - 100
P - 60
Q - 48
S - 36

After the redistribution it looks like :
R - 0
P - 60
Q - 88
S - 96

And the fraction Q/S = 88/96 = 11/12
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