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Nevermind - misread your answer. You got it.
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jimmyjamesdonkey
If the volume of cube A is twice that of cube B, the side of cube A is how many time that of cube B?

1) 1/2
2) cubed rt(2)
3) 3*cubed rt(2)
4) 2
5) 8

OA to follow.
:?:


B : This looked like a plain vanilla. Was there any trick involved??
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Let side of cube A be x, side of cube B be y

Volume of A = x^3
Volue of B = y^3

x^3 = 2y^3
x = 2^1/3(y)

So the side of A is cube root (2) of B
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ywilfred is correct:

X = one cube
Y = second cube

x^3 = y^3*2 ---> (one volume is twice the other volume)

3sqrt(2)^3 = 2

x^3 = y^3*3sqrt(2)^3

x^3 = (y*3sqrt(2))^3 ---> the same way that 2^2*3^2 = 6^2

x = y*3sqrt(2)

the answer is (B) = cubed rt(2) = 3sqrt(2)

:-D
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Volume of cube is directly proportional to the cube of side
Volume of CubeA/Volume of Cube B = [Side of cube A/side of cube B]^3

in this question
Volume of A/Volume of B = 2

[Side of cube A/side of cube B]^3 = 2

Side of cube A/side of cube B = cubic root (2)

Side of cube A = cubic root (2) * Side of B

Hence Answer is B
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jimmyjamesdonkey
If the volume of cube A is twice that of cube B, the side of cube A is how many time that of cube B?

A. 1/2
B. \(\sqrt[3]{2}\)
C. \(3\sqrt[3]{2}\)
D. 2
E. 8

3-D Geometry Questions Directory: 3-d-geometry-questions-171024.html
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any cubes are similar each other meaning that the ratio of theirs volumes is third degree of their side's ratio, so

a^3/2b^3=sqrt^3 of a^3/sqrt^3 of (2b)^3=a/sqrt^3 of 2*b

B
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Let volume of cube B = 1 = 1 * 1 *1

Then volume of cube A = 2 \(= 2^{\frac{1}{3}} * 2^{\frac{1}{3}} * 2^{\frac{1}{3}}\)

Dimension of Cube A is \(2^{\frac{1}{3}}\) times that of dimension of cube B

Answer = B
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Concept is Cube
Cube _ 6 Sides , Volume is S^3 , Given 2 Cubes
S^3 = 2 x S^3
???Confused
Changing the variables as two Different Cubes
a^3 = 2 b^3 ( A is twice that of B)
a = ? ??
a x a^2 = 2 x b^3
a = 2 x b^3 /a^2 ?????
Next? :idea: ?

Is my thought process is right??
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kanusha
Concept is Cube
Cube _ 6 Sides , Volume is S^3 , Given 2 Cubes
S^3 = 2 x S^3
???Confused
Changing the variables as two Different Cubes
a^3 = 2 b^3 ( A is twice that of B)
a = ? ??
a x a^2 = 2 x b^3
a = 2 x b^3 /a^2 ?????
Next? :idea: ?

Is my thought process is right??


Instead of taking 2 variables, just try plugins... Please look at posts above
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kanusha
Concept is Cube
Cube _ 6 Sides , Volume is S^3 , Given 2 Cubes
S^3 = 2 x S^3
???Confused
Changing the variables as two Different Cubes
a^3 = 2 b^3 ( A is twice that of B)
a = ? ??
a x a^2 = 2 x b^3
a = 2 x b^3 /a^2 ?????
Next? :idea: ?

Is my thought process is right??


Here you have to find the relation between Side od Cube A and Side of Cube B

Let Sa = side of cube A
And Sb = Side of cube B

given, Va = 2* Vb

(Sa^3) = 2* (Sb^3)--------------- Till this step you are correct. See the below explanation to clear the doubt.

Taking Cube root on both sides

Sa = 2^(1/3) * Sb


Therefore answer is B
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jimmyjamesdonkey
If the volume of cube A is twice that of cube B, the side of cube A is how many time that of cube B?

A. 1/2
B. \(\sqrt[3]{2}\)
C. \(3\sqrt[3]{2}\)
D. 2
E. 8

Volume A= 2 Volume B

Side^3 (A) = 2 Side ^3 (B)
Side (A) = 2 ^1/3X Side (B)

B is the answer
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