sayan640
silhouette
I am confused because I have a different answer...
|----5---10----20----30----35----40-----50----|
10,10,10,10 are the only open times it is possible to wait 6+ minutes
It is allowed 6 minutes that the person can wait before they are counted
4+4+4+4 = 16/60 = 4/15
Yet this is wrong?
How did you get 30 and 40? The express buses run every hour starting at 10 mins past. So the express buses run only at 10 mins past.
Local buses run every 15 mins starting at 5 mins past so they run at 5, 20, 35 and 50 mins past the hour.
So buses run at following mins past the hour:
...5....10...20....35....50
This means a person arriving between 10 and 14, 20 and 29, 35 and 44, and 50 and 59 must wait for more than 6 mins.
4 + 9 + 9+ 9 = 31 mins
Probability = 31/60
If he arrives at 6:14 , then he will have to wait for 6 minutes as the next bus is at 6:20.
Why are you then including 6:14 ? We need those time-instants for which wait-period is more than 6 minutes.
VeritasKarishma ?[/quote]
Express: 6:10, 7:10, 8:10, 9:10 ...
Local: 6:05, 6:20, 6:35, 6:50, 7:05, 7:20, 7:35, 7:50 ...
If passenger arrives in these time slots between 6:00 to 7:00, he will need to wait more than 6 mins.
6:10 to 6:14 (arrives just a microsecond before the clock turns 6:14 so the minute of 6:13 to 6:14 is also added)
From
6:10 to 6:11, 1 min
from 6:11 to 6:12, 1 min
from 6:12 to 6:13, 1 min
from 6:13 to 6:14, 1 min
Total 4 mins from 6:10 to 6:14.[/quote]
VeritasKarishma maa'm, Why do you say "........from exact 6:10 to 6:11 ..." ?
Why are you considering the "6:10 " moment....?There is an express bus at 6:10 ...right ?I apologize if I am over-analyzing.
VeritasKarishmaVeritasKarishma