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13 Mar 2008, 09:43
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6 guys (let's call them ABCDEF) sit around a circular table. If the AB must always sit together, and C must face the door, how many arrangements are possible? please explain your work...
13 Mar 2008, 10:19
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48
1. "C must face the door" - the condition fixes circular shifts.
2. "the AB must always sit together" - we can consider AB one object, but count it twice as AB and BA .
3. We have 4 objects (3 guys and one couple
): 4P4=4!=24
4. finally, N=24*2=48
1. "C must face the door" - the condition fixes circular shifts.
2. "the AB must always sit together" - we can consider AB one object, but count it twice as AB and BA .
3. We have 4 objects (3 guys and one couple
): 4P4=4!=244. finally, N=24*2=48
): 4P4=4!=24
