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Hussain15
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IMO its D.. OA please

1. AC > BC

=> AC-BC >0
(A-B) C > 0 true

as C< 0
and A-B < 0...thus true.

2. Its also true

Thus I and II only
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gurpreetsingh
IMO its D.. OA please

1. AC > BC

=> AC-BC >0
(A-B) C > 0 true

as C< 0
and A-B < 0...thus true.

2. Its also true

Thus I and II only

Nice explanation!! Kudos!!

OA is "D".
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if a<b and c<0
then: a+c<b+0
can someone explain, how ii is true?
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since c<0 and a<b so if we multiply a negative quantity to a smaller quantity then it turns out to be bigger in value(in both cases when a,b are negative or positive).so a is correct..simmilarly for b
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Nice question. Its easy to miss that even statement 1 is be true. Thanks gurpreetsingh.
Answer: D
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Answer should be A.

Try with values. 2nd statement fails for a=-1, b=1, c=-1
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prabhakarsharma
Answer should be A.

Try with values. 2nd statement fails for a=-1, b=1, c=-1

Please try again.

a + c = -1 -1 = -2
b + c = 1 -1 = 0

=> a + c < b + c
(II) is correct.

Hope it helps
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D is correct. as it works for both +ve and -ve numbers
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Hussain15
If a < b and c < 0, which of the following are true?

I. ac > bc
II. a + c < b + c
III. a - c > b - c

A. I only
B. II only
C. III only
D. I and II only
E. Neither

I. ac > bc
- we can divide both sides of inequality by c. We are given that c<0. Dividing by a negative number flips the inequality sign; after dividing by c, the inequality becomes a < b. We are told in the stem that a < b. TRUE

II. a + c < b + c
- since we are told that c is negative, the inequality can be re-written as: a - c < a -c. Adding c to both sides cancels the variable out. This then comes a < b, which we see is true given the stem. TRUE

III. a - c > b - c
- since c < 0, we can re-write this inequality as
a -(-c) > b - (-c). This turns into a + c > b + c, where when we cancel out the c variable, the inequality becomes a > b. This goes against the given information of a < b in the stem.
NOT TRUE

I and II only

Option D
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