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ykaiim
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Hi,

I tried to first draw the diagram and when u take a close look u can easily tell what would be the answer 8-) .
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:idea: apparently, the answer can be found just by observing the choices.

we know that BC > AB => (BC - BD) > (AB - BD) => QC > AP

ie, the only logical choice is 4.
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shaselai
is answer choice 4?

Well since you know the radis from 36-25 = 11 r= sqrt(11) you can find Ap QC with 6-sqrt(11) and 8 - sqrt(11). Also, another thing to notice is that PB and BQ will be the same value since they are radius for circle B. since AB is shorter than BC you know the ratio will be a smaller value to a larger value so 4 seems to fit the bill..


Where you get 25 from ........... (above in red)
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xcusemeplz2009
if we can know the length of BD we can find out AP and QC
since BP=BQ=BD=radius
now there are two ways to find out the length of BD
one is using pythagoras theorem another is using area(hero's formula)
pythagoras :
BD^2=AB^2-AD^2=BC^2-DC^2{DC=AC-AD}
using the above eqn we will get BD=24/5

AP=6-24/5=6/5
QC=8-24/5=16/5
ratio=6/16=3/8

hero's formula
s=a+b+c/2=(6+8+10)/2=12
area=Sqrt(s(s-a)(s-b)(s-c)=24
area is also=1/2 * BD*AC=5BD
so BD=24/5
rest is same


how do we know the value of AD and DC?
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ans should be 3/8

as per question abc is right angled at B and using similar triangle in triangle ABC and ABD

we get x = 24/5 , join line DP and DQ , both will be the radius, thus x = DP = DQ

so AP = 6 -24/5 = 6/5

QC = 8-25/5 = 16/5

ratio AP:QC = 6/16 = 3/8
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i still dont get it
Can you please explain in more details how you get 24/5

This question is testing my patience!!!!
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Draw a triangle ABC with b =90 and draw a perpendicular from b to D as given

now take BD = x

Since ABC and ABD are similar triangles.
We take ratio of the sides of equal angles
angle opp x is 90-c and opp BC is 90-c
similarly angle opp 90 in ABD is AB and in ABC is AC

x/BC = AB/AC => X = 24/5

I hope this helps.
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In the triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets the side AC at D. A circle of radius BD (with center B) is drawn. If the circle cuts AB and BC at P and Q respectively, the AP:QC is equal to
1. 1:1
2. 3:2
3. 4:1
4. 3:8

Is there any smarter/shorter way?
try this :)
since it is right angle triangle, altitude BD is given by formula BD = BC*AB/AC => BD = 6*8/10 = 24/5
also from question stem, BP = BQ = BD = 24/5 ( radius of circle )
hence, AP = AB-BP = 6-24/5 = 6/5 and QC = BC-BQ = 8-24/5 = 16/5
so, AP:QC = 6/5:16/5 = 3:8
for the formula and picture please refer following link:
https://gmatclub.com/forum/what-to-remember-in-gmat-quant-all-time-92840.html
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xcusemeplz2009
if we can know the length of BD we can find out AP and QC
since BP=BQ=BD=radius
now there are two ways to find out the length of BD
one is using pythagoras theorem another is using area(hero's formula)
pythagoras :
BD^2=AB^2-AD^2=BC^2-DC^2{DC=AC-AD}
using the above eqn we will get BD=24/5

AP=6-24/5=6/5
QC=8-24/5=16/5
ratio=6/16=3/8
how do we know the value of AD and DC?
no need to find AD and DC
we know that AD+DC=10 -----> DC=10-AD and have eqn AB^2-AD^2=BC^2-DC^2 put DC=10-AD
or AB^2-AD^2=BC^2-(10-AD)^2----->solving we get BD=24/5
HTH
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ykaiim
In the triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets the side AC at D. A circle of radius BD (with center B) is drawn. If the circle cuts AB and BC at P and Q respectively, the AP:QC is equal to
1. 1:1
2. 3:2
3. 4:1
4. 3:8

Is there any smarter/shorter way?

First of all we should spot that ABC is a right triangle with right angle at B, as 6-8-10 is a Pythagorean triplet and AC, the longest side, is the hypotenuse.

Next in right triangle: \(\frac{height}{leg_1}=\frac{leg_2}{hypotenuse}\) --> \(\frac{BD}{AB}=\frac{BC}{AC}\) --> \(\frac{BD}{6}=\frac{8}{10}\) --> \(BD=\frac{24}{5}\).

Now, \(BD=BP=BQ=radius=\frac{24}{5}\).

\(\frac{AP}{QC}=\frac{BA-BP}{BC-BQ}=\frac{6-\frac{24}{5}}{8-\frac{24}{5}}=\frac{3}{8}\).

Answer: D (\(\frac{3}{8}\))
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One more approach to solve such problems:

Triangle ABC is a right angled triangle. So, we can use the area calculation method:
1/2×BC×AB=1/2×BD×AC >>> 6×8=BD×10

This results BD = 4.8 and BP= BQ= 4.8
So, AP=AB–BP=6–4.8=1.2 and similarly, CQ=BC–BQ=8–4.8=3.2.

Finally, we can derive the result by taking ratio:
AP:CQ=1.2:3.2=3:8
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Got it now - Thanks Bunuel (Didnt know about this property of right triangle)
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Ans 4, as QC is greater than AP
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let r be the radius.

AP=6-x; CQ=8-x
CQ is greater than AP so the only possible ans is 3/8
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A crude way to solve this would be as follows:

Draw the triangle and the circle.
Observing the circle, it will cut AB closer to A than when cutting BC. When cutting BC, it will cut BC farther from the point C.

So, the AP is smaller than QC. Only option that displays such a nature is Option D..i.e 3:8

if additionally any other option were given, then the cycle of solving starts.
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