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Im trying to answer this another way but I can't seem to think what I'm doing wrong

So we have

PQ = 360
(0.9P)(Q+12) = 360

We need to find 120P

Now if we reduce 10% on P and still get the same result then Q increases 10%
So Q + 12 = 11/10 Q --> Q = 120

Therefore P is equal to 3.

And we have that 120P = 360.

I don't quite know what I can't get the answer 400 following this approach, could any expert please advise

Thanks a lot!
Cheers
J
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Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.

A. 360
B. 380
C. 400
D. 406
E. 412

Im trying to answer this another way but I can't seem to think what I'm doing wrong

So we have

PQ = 360
(0.9P)(Q+12) = 360

We need to find 120P

Now if we reduce 10% on P and still get the same result then Q increases 10%
So Q + 12 = 11/10 Q --> Q = 120

Therefore P is equal to 3.

And we have that 120P = 360.

I don't quite know what I can't get the answer 400 following this approach, could any expert please advise

Thanks a lot!
Cheers
J

P reduces 9/10 times, thus Q increases 10/9 times: Q + 12 = 10/9*Q --> Q = 108.

Alternatively you could solve the system of equations: PQ = 360 and (0.9P)(Q+12) = 360 to get the same result.
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Bunuel
jlgdr
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.

A. 360
B. 380
C. 400
D. 406
E. 412

Im trying to answer this another way but I can't seem to think what I'm doing wrong

So we have

PQ = 360
(0.9P)(Q+12) = 360

We need to find 120P

Now if we reduce 10% on P and still get the same result then Q increases 10%
So Q + 12 = 11/10 Q --> Q = 120

Therefore P is equal to 3.

And we have that 120P = 360.

I don't quite know what I can't get the answer 400 following this approach, could any expert please advise

Thanks a lot!
Cheers
J

P reduces 9/10 times, thus Q increases 10/9 times: Q + 12 = 10/9*Q --> Q = 108.

Alternatively you could solve the system of equations: PQ = 360 and (0.9P)(Q+12) = 360 to get the same result.

I see were my mistake was. Well but replacing and all into (2) is too much work. Once with Q then you can solve much easier in my opinion

Thanks again buddy
Cheers
J
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jlgdr
Bunuel
jlgdr
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.

A. 360
B. 380
C. 400
D. 406
E. 412

Im trying to answer this another way but I can't seem to think what I'm doing wrong

So we have

PQ = 360
(0.9P)(Q+12) = 360

We need to find 120P

Now if we reduce 10% on P and still get the same result then Q increases 10%
So Q + 12 = 11/10 Q --> Q = 120

Therefore P is equal to 3.

And we have that 120P = 360.

I don't quite know what I can't get the answer 400 following this approach, could any expert please advise

Thanks a lot!
Cheers
J

P reduces 9/10 times, thus Q increases 10/9 times: Q + 12 = 10/9*Q --> Q = 108.

Alternatively you could solve the system of equations: PQ = 360 and (0.9P)(Q+12) = 360 to get the same result.

I see were my mistake was. Well but replacing and all into (2) is too much work. Once with Q then you can solve much easier in my opinion

Thanks again buddy
Cheers
J

Actually you can get \(Q + 12 = \frac{10}{9}*Q\) from the system of equations we have quite easily. Divide \((0.9P)(Q+12) = 360\) by \(PQ = 360\):

\(\frac{0.9(Q+12)}{Q} = 1\) --> \(0.9(Q+12) = Q\) --> \(Q + 12 = \frac{10}{9}*Q\).

Hope it helps.
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Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.

Method 1:
Let price per mango = x. Let number of mangoes be n. Then, nx = 360.
Now price = 0.9x; number of mangoes = n + 12. Total amount = 0.9x*(n+12) = 360.
nx = 0.9nx + 10.8x => 0.1nx = 10.8x => n = 108 => x = 360/108 = 3.33
Original price of 120 mangoes = 120*3.33 = 400.

Method 2:
Let price per mango be x. Then, 360/(0.9x) - 360/x = 12
=> 400/x - 360/x = 12 => 40/x = 12 => x = 40/12.
Price of 120 mangoes = 120 x = 120 *40/12 = 400
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Price ................ Qty .............. Total

p ........................ \(\frac{360}{p}\) ................ 360
(Assume)

Price reduction = 10%; Qty increase = 12

\(\frac{90p}{100}\) ............... \(\frac{360}{p} + 12\) ............. 360

Setting up the equation

\(\frac{90p}{100} * (\frac{360}{p} + 12) = 360\)

\(p = \frac{40}{12}\)

Price for 120 Mangoes

\(= \frac{40}{12} * 120 = 400\)

Answer = C
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