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Wow, thank you Bunuel, I would have totally gotten this wrong on the test haha.

Better here than during the real GMAT.
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Creeper300
Z is a two digit positive integer, Z is equal to 7 times the sum of its digits. Is Z=84?

1. Sum of its digits is 12
2. Product of its digits is 32

let Z = 10a + b, where a is the tens place digit and b is the ones place digit

10a + b = 7 (a+b) => a = 2b ----- (0)


(1) states that the (a+b) = 12
using (1) and (0), the only possible answer is 84


(2) states that axb = 32
using (2) and (0), the only possible answer is 84.
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my brain is not clicking, but can someone explain how a = 2b?

i'm understanding this part: 10a + b = 7 (a+b)
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my brain is not clicking, but can someone explain how a = 2b?

i'm understanding this part: 10a + b = 7 (a+b)

Well 10a + b is just another way of writing a two digits number.

For example, if Z = 65, then Z = 65 = 10*6 + 5. where 6 = "a" and 5 = "b"
taking things further, we can express any length number using the notation above.

so if Z = 12345.6 = 10000*1 + 1000*2 + 100*3 + 10*4 + 5 + 0.1*6

and since we are given the fact that Z = 7 * (sum of the digits) = 7* (a+b)
we are able state that 10a + b = 7 (a+b).
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gtr022001
my brain is not clicking, but can someone explain how a = 2b?

i'm understanding this part: 10a + b = 7 (a+b)

\(10a + b = 7 (a+b)\) --> \(10a+b=7a+7b\) --> \(3a=6b\) --> \(a=2b\).

Hope it's clear.
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ah, crystal clear, thanks guys!
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Thanks for post.. Nice question
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