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anilnandyala
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Bunuel
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micahman
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Bunuel

Um, I thought 'a' is sufficient enough!

Consider the statement x(y+5)

i. If y is odd, then y+ 5 is even --> x(y+5) becomes x * even = even --> x here has to be even.

ii. If y is even, then y+5 is odd --> x(y+5) becomes x * odd = even --> For this to be true, x has to be even.

Why isn't the answer 'A'?­
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e3thekid
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prabhanjan19
Bunuel

Um, I thought 'a' is sufficient enough!

Consider the statement x(y+5)

i. If y is odd, then y+ 5 is even --> x(y+5) becomes x * even = even --> x here has to be even.

ii. If y is even, then y+5 is odd --> x(y+5) becomes x * odd = even --> For this to be true, x has to be even.

Why isn't the answer 'A'?­

In your first scenario, if (y+5) is even, x does not have to be even for the product to be even.

X = odd
Odd * even = even

X can be even or odd, so you get a YES/NO for the stem; therefore statement 1 is insufficient alone.

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anilnandyala
If x and y are integers, is x an even integer?

(1) x(y + 5) even integer
(2) 6y^2 + 41y + 25 is even integer­





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