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E
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Difficulty:
25%
(medium)
Question Stats:
76% (01:29) correct
24%
(01:17)
wrong
based on 182
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If x, y, and z are consecutive integers, and x < y < z , is x even?
(1) x + y is odd.
(2) x + z is even.
(1) x + y is odd.
(2) x + z is even.
27 Jul 2011, 05:18
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bschool83
(1) Insufficient - x, and y are given as consecutive integers, so one number in x and y has to be even and one has to be odd, like x=1 and y =2 or x=2 and y=3....but the sum will always be odd. so this statement doesnt gives any information at all.
2) Insufficient. - It's given that x y and z are consecutive integers in order x ,y, z....so sum of x and z will always be even. you can see for example if x=1 and z=3 sum =4 (even) , similarly if x=2 and z=4, sum = 6 even . so this too doesnt adds any info. even +even = always even and odd + odd = always even.
together too they are insufficient because neither of the statements add any info to what is already given in question. Answer E.
04 Oct 2017, 00:53
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is x even, with x,y,z being consecutive and x<y<z
St 1: x+ y = odd. And x< y
Case 1: 1+2 = 3 (ODD); 4+5 = ODD; 5+6 (ODD)
Not suff x can be odd or even answer is ODD
St 2: x + z = even. x = 4, y = 5, z = 6 answer is even. x =3, y = 4, z= 6 answer is even.
odd + odd = even and even+ even = even
Not suff
1) + 2) No conclusion. Ans is E
What is the OA?
St 1: x+ y = odd. And x< y
Case 1: 1+2 = 3 (ODD); 4+5 = ODD; 5+6 (ODD)
Not suff x can be odd or even answer is ODD
St 2: x + z = even. x = 4, y = 5, z = 6 answer is even. x =3, y = 4, z= 6 answer is even.
odd + odd = even and even+ even = even
Not suff
1) + 2) No conclusion. Ans is E
What is the OA?
