Last visit was: 25 Apr 2026, 07:26 It is currently 25 Apr 2026, 07:26
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
Berbatov
Joined: 18 Aug 2011
Last visit: 03 Nov 2018
Posts: 29
Own Kudos:
186
 [8]
Given Kudos: 6
Posts: 29
Kudos: 186
 [8]
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,827
Own Kudos:
811,199
 [9]
Given Kudos: 105,878
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,827
Kudos: 811,199
 [9]
7
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
avatar
jagdeepsingh1983
Joined: 14 Mar 2011
Last visit: 16 Aug 2022
Posts: 32
Own Kudos:
Given Kudos: 21
Posts: 32
Kudos: 172
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
Berbatov
Joined: 18 Aug 2011
Last visit: 03 Nov 2018
Posts: 29
Own Kudos:
Given Kudos: 6
Posts: 29
Kudos: 186
Kudos
Add Kudos
Bookmarks
Bookmark this Post
jagdeepsingh1983
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

(1) x = 4y
(2) x - 3y = 10

1. x=4y tells us x is multiple of 4 not we not sure about Y, but both divisible by 10-Not sufficient
2 x-3y=10, means x is 10 number greater than y but it can be if x 130 y can be 120 but not sure Not Sufficient
1010-1000, 210-200 not sufficient

Now combining both we get Y=10 & x=40 which means 10 is HCF

Remember there is difference between LCM & HCF

I think you forgot the "3 times" in (2)
User avatar
Capricorn369
Joined: 11 May 2011
Last visit: 06 May 2019
Posts: 232
Own Kudos:
Given Kudos: 84
GMAT 1: 680 Q49 V30
Posts: 232
Kudos: 225
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Berbatov
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

(1) x = 4y
(2) x - 3y = 10

B is my answer.

Reason -

1. x = 4y
if x = 40, y =10 -> GCF = 10
if x = 80, y =20 -> GCF = 20 ----- not sufficient.

(2) x - 3y = 10
if y = 10, y= 40 -> GCF = 10
if y = 20, y= 70 -> GCF = 10
if y = 30, y= 100 -> GCF = 10 ------- Sufficient.

Hope it helps.!
User avatar
jamifahad
Joined: 03 Mar 2010
Last visit: 14 Mar 2015
Posts: 256
Own Kudos:
Given Kudos: 22
Posts: 256
Kudos: 1,735
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Easiest way to do this is to pick numbers.

Berbatov
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

(1) x = 4y
(2) x - 3y = 10

Stmt1: x=4y
y=10
x-40
10 is the GCF.
y=100
x=400
100 is the GCF. Yes and No. Not sufficient.

Stmt2: x-3y=10
x=3y+10
y=10
x=40
GCF=10
y=100
x=310
GCF=10
y=50
x=160
GCF=10 Sufficient.
OA B.
User avatar
reatsaint
Joined: 06 Feb 2011
Last visit: 22 Dec 2012
Posts: 44
Own Kudos:
Given Kudos: 11
WE:Information Technology (Computer Software)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(1) Putting values, we can have 40,10 or 400,100. GCD can be 10 or 100. NOT SUFFICIENT.
(2) x - 3y = 10, again putting values, we can have only 40,10 or 70,20.
Now let us substitute x = 10a and y = 10b.
10a – 30b = 10,
Thus a = (10 +30b) / 10
We can conclude for all values of b, 10 + 30b must be a multiple of 10, hence GCD of x and y is indeed 10.
SUFFICIENT.
Hence ans is B
User avatar
Daeny
Joined: 31 Aug 2012
Last visit: 22 Jan 2013
Posts: 8
Own Kudos:
Given Kudos: 13
Posts: 8
Kudos: 185
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is there any way other than substituting values?
User avatar
EvaJager
Joined: 22 Mar 2011
Last visit: 31 Aug 2016
Posts: 513
Own Kudos:
Given Kudos: 43
WE:Science (Education)
Posts: 513
Kudos: 2,371
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Berbatov
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

(1) x = 4y
(2) x - 3y = 10

If 10 is the greatest common divisor of \(x\) and \(y\) then \(x=10a, \, y=10b\) for some positive integers \(a\) and \(b\), where \(a\) and \(b\) are co-prime (meaning their greatest common divisor is 1).

(1) Obviously not sufficient. It just states that \(x\) is 4 times bigger than \(y\), which can hold even without the two numbers being divisible by 10.
For example \(x=4,\,y=1.\)

(2) Again, not sufficient. \(x=3y+10\), \(x\) and \(y\) not necessarily divisible by 10. For example \(x=13,\,y=1.\)

(1) and (2) together: solving the two equations we obtain unique values for \(x\) and \(y\): \(x=40,\,y=10.\)
Sufficient.

Answer C
avatar
sravs27
Joined: 03 Sep 2012
Last visit: 02 Jun 2016
Posts: 1
Given Kudos: 1
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Guess they have mentioned in the question that x & y are divisible by 10. So, x & y cant take values 13 and 1. But still I feel 2nd statement is not sufficient.
User avatar
EvaJager
Joined: 22 Mar 2011
Last visit: 31 Aug 2016
Posts: 513
Own Kudos:
Given Kudos: 43
WE:Science (Education)
Posts: 513
Kudos: 2,371
Kudos
Add Kudos
Bookmarks
Bookmark this Post
sravs27
Guess they have mentioned in the question that x & y are divisible by 10. So, x & y cant take values 13 and 1. But still I feel 2nd statement is not sufficient.

Thanks.
I am such an astronaut...

So, let's try again:

Assume \(x=10a\) and \(y=10b\), for some positive integers \(a\) and \(b.\)
\(x\) and \(y\) have 10 as their greatest common divisor if and only if \(a\) and \(b\) are co-prime (their greatest common divisor is 1).

(1) \(x=4y\) translates into \(10a=40\)b or \(a=4b\).
\(a\) and \(b\) can be co-prime only if \(b=1.\)
Not sufficient.

(2) \(x-3y=10\) becomes \(10a-30b = 10\) or \(a-3b=1\).
If \(a\) and \(b\) have a common divisor \(d\) (some positive integer), then \(a=md\) and \(b=nd\) for some positive integers \(m\) and \(n.\)
It follows that \(dm-3dn = d(m-3n)=1\), which means that \(d\) must be a divisor of 1, so \(d=1.\)
It means that \(a\) and \(b\) are co-prime.
Sufficient.

Answer B.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,827
Own Kudos:
Given Kudos: 105,878
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,827
Kudos: 811,199
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bumping for review and further discussion.
User avatar
suk1234
Joined: 29 Sep 2013
Last visit: 04 Jul 2016
Posts: 37
Own Kudos:
Given Kudos: 48
Posts: 37
Kudos: 194
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

Given: \(x=10m\) and \(y=10n\), for some positive integers \(m\) and \(n\).

(1) x = 4y. If \(x=40\) and \(y=10\), then the answer is YES but \(x=80\) and \(y=20\), then the answer is NO. Not sufficient.

(2) x - 3y = 10 --> \(10m-3*(10n)=10\) --> \(m-3n=1\) --> \(m=3n+1\). \(m\) and \(3n\) are consecutive integers. Any two consecutive positive integers are co-prime, which means that they do not share any common factor but 1. For example: 3 and 4, 5 and 6, 100 and 101, are consecutive integers and they do not share any common factor bu 1. So, \(m\) and \(3n\) do not share any common factors but 1, which means that \(m\) and \(n\) also do not share any common factors but 1, therefore the greatest common factor of \(x=10m\) and \(y=10n\) is 10. Sufficient.

Answer: B.

Hope it's clear.

I am Sorry I can't get it, how are \(m\) and \(3n\) consecutive integers?


Thanking you in advance!
User avatar
abhinav11
Joined: 04 Sep 2012
Last visit: 02 Apr 2016
Posts: 114
Own Kudos:
174
 [1]
Given Kudos: 27
Posts: 114
Kudos: 174
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
suk1234
Bunuel
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

Given: \(x=10m\) and \(y=10n\), for some positive integers \(m\) and \(n\).

(1) x = 4y. If \(x=40\) and \(y=10\), then the answer is YES but \(x=80\) and \(y=20\), then the answer is NO. Not sufficient.

(2) x - 3y = 10 --> \(10m-3*(10n)=10\) --> \(m-3n=1\) --> \(m=3n+1\). \(m\) and \(3n\) are consecutive integers. Any two consecutive positive integers are co-prime, which means that they do not share any common factor but 1. For example: 3 and 4, 5 and 6, 100 and 101, are consecutive integers and they do not share any common factor bu 1. So, \(m\) and \(3n\) do not share any common factors but 1, which means that \(m\) and \(n\) also do not share any common factors but 1, therefore the greatest common factor of \(x=10m\) and \(y=10n\) is 10. Sufficient.

Answer: B.

Hope it's clear.

I am Sorry I can't get it, how are \(m\) and \(3n\) consecutive integers?


Thanking you in advance!


AS Bunuel Proved in the second statement m = 3n + 1 that means m is 1 greater than 3n or m and 3n are consecutive.

I hope it is clear now.

I am following GMAT quant since 2 months and I am in awe of how Bunuel goes about each question so thoroughly and perfectly. I wish I may achieve half of that.

Probably "the greatest" Mathematician I have come across all my life :roll:

Regards,
Abhinav
User avatar
jlgdr
Joined: 06 Sep 2013
Last visit: 24 Jul 2015
Posts: 1,302
Own Kudos:
Given Kudos: 355
Concentration: Finance
Posts: 1,302
Kudos: 2,977
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

Given: \(x=10m\) and \(y=10n\), for some positive integers \(m\) and \(n\).

(1) x = 4y. If \(x=40\) and \(y=10\), then the answer is YES but \(x=80\) and \(y=20\), then the answer is NO. Not sufficient.

(2) x - 3y = 10 --> \(10m-3*(10n)=10\) --> \(m-3n=1\) --> \(m=3n+1\). \(m\) and \(3n\) are consecutive integers. Any two consecutive positive integers are co-prime, which means that they do not share any common factor but 1. For example: 3 and 4, 5 and 6, 100 and 101, are consecutive integers and they do not share any common factor bu 1. So, \(m\) and \(3n\) do not share any common factors but 1, which means that \(m\) and \(n\) also do not share any common factors but 1, therefore the greatest common factor of \(x=10m\) and \(y=10n\) is 10. Sufficient.

Answer: B.

Hope it's clear.

We can also note on statement 2 that since X and Y are both multiples of 10 and the difference is a multiple of 10 then 10 must be their GCF, if x and y had a higher GCF say like 20,30,40 etc... then the difference of two multiples of 20 will never yield 10 as a difference, same with others

Just my 2cents

Additional note: If the second statement were x-y = 10 we could also know that the GCF cannot exceed 10 because the GCF is always less than the difference between two numbers and exactly 10 when these two numbers are consecutive integers. Therefore we would know that these two numbers x and y are consecutive integers.

But that's for another problem I guess

Hope it helps
Gimme some freaking Kudos!!
J :)
User avatar
mvictor
User avatar
Board of Directors
Joined: 17 Jul 2014
Last visit: 14 Jul 2021
Posts: 2,118
Own Kudos:
Given Kudos: 236
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE:General Management (Transportation)
Products:
GMAT 1: 650 Q49 V30
Posts: 2,118
Kudos: 1,277
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Berbatov
If both x and y are positive integers that are divisible by 10, is 10 the greatest common factor of x and y?

(1) x = 4y
(2) x - 3y = 10

1. x=40, y = 10 -> GCF = 10 or X=200, y=50. GCF=50 -> A and D out.
2. x-3y=10 or
(x-10)/3 = y
so (x-10)/3 is a number divisible by 10.
x=40 - y=10
x=70 - y=20
x=100 - y=30
so as we can see, GCF always is 10. sufficient.
B is the answer.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,984
Own Kudos:
Posts: 38,984
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109827 posts
498 posts
212 posts