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Difficulty:
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Question Stats:
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22%
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To install cable television in a home, a certain cable company charges a basic fee of $30 plus a fee of $20 for each cable outlet installed in the home. How much did the cable company charge the Horace family for installing cable television in their home?
(1) The cable company installed three cable outlets in the Horace family home.
(2) The amount that the cable company charged the Horace family for installing cable television in their home was equivalent to an average ( arithmetic mean) charge of the $30 per cable outlet installed.
(1) The cable company installed three cable outlets in the Horace family home.
(2) The amount that the cable company charged the Horace family for installing cable television in their home was equivalent to an average ( arithmetic mean) charge of the $30 per cable outlet installed.
24 Aug 2015, 22:49
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Stiv
A logical solution:
Total charge = 30 + 20 * Number of Cable Outlets
(1) The cable company installed three cable outlets in the Horace family home.
Directly gives you the number of cable outlets. Sufficient
(2) The amount that the cable company charged the Horace family for installing cable television in their home was equivalent to an average ( arithmetic mean) charge of the $30 per cable outlet installed.
On the whole, the charge was equivalent to $30 for each outlet. The extra $10 was charged because $30 basic fee was spread across the cable outlets. To give $10 extra to each cable outlet, there must have been 3 cable outlets.
So total charge must have been 3*30 = 90
Sufficient.
Answer (D)
02 May 2012, 01:14
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To install cable television in a home, a certain cable company charges a basic fee of $30 plus a fee of $20 for each cable outlet installed in the home. How much did the cable company charge the Horace family for installing cable television in their home?
(1) The cable company installed three cable outlets in the Horace family home. Total cost=$30+$20*3. Sufficient.
(2) The amount that the cable company charged the Horace family for installing cable television in their home was equivalent to an average (arithmetic mean) charge of the $30 per cable outlet installed. Say the number of outlets is x, then Total cost=$30+$20*x and the average is ($30+$20*x)/x --> ($30+$20*x)/x=30. We can solve for x. Sufficient.
Answer: D.
(1) The cable company installed three cable outlets in the Horace family home. Total cost=$30+$20*3. Sufficient.
(2) The amount that the cable company charged the Horace family for installing cable television in their home was equivalent to an average (arithmetic mean) charge of the $30 per cable outlet installed. Say the number of outlets is x, then Total cost=$30+$20*x and the average is ($30+$20*x)/x --> ($30+$20*x)/x=30. We can solve for x. Sufficient.
Answer: D.
