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Sub 505 (Easy)|   Percent and Interest Problems|                           
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Bunuel
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Bunuel

If $5,000 invested for one year at p percent simple annual interest yields $500, what amount must be invested at k percent simple annual interest for one year to yield the same number of dollars?

(1) k = 0.8p
(2) k = 8
Hi,

Difficulty level: 600

SI (Simple Interest) = \(\frac{PRT}{100}\),
where, P = Principal,
R = Rate in percentage,
T = Time

Thus, \(500 = \frac {5000*p*1}{100}\)
or p = 10%

New Principal invested depends on value of k

Using (1),
k=0.8*p=8%
\(P=\frac {100SI}{RT}\\
=\frac {100*500}{8*1}\). Sufficient.

Using (2),
k=8%
\(P=\frac {100SI}{RT}\\
=\frac {100*500}{8*1}\). Sufficient.

Answer (D),

Regards,
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Bunuel
If $5,000 invested for one year at p percent simple annual interest yields $500, what amount must be invested at k percent simple annual interest for one year to yield the same number of dollars?

(1) k = 0.8p
(2) k = 8

Since interest amount = principal x interest rate x time, we have:

500 = 5000 x p/100 x 1

500 = 50 x p

p = 10

Let A = principal that yields $500 interest at k percent simple annual interest rate in one year, so we have:

500 = A x k/100 x 1

50000/k = A

So if we know the value of k, we can determine the value of A.

Statement One Alone:

k=0.8p

Since p = 10, then k = 0.8(10) = 8. Since we know the value of k, we can determine the value of A (without actually determining it). Statement one alone is sufficient.

Statement Two Alone:

k=8

Since we know the value of k, we can determine the value of A (without actually determining it). Statement two alone is sufficient.

Answer: D
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Bunuel
If $5,000 invested for one year at p percent simple annual interest yields $500, what amount must be invested at k percent simple annual interest for one year to yield the same number of dollars?

(1) k = 0.8p
(2) k = 8­





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

[email protected]
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