Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
19 Nov 2014, 08:18
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
52% (02:15) correct
48%
(02:01)
wrong
based on 367
sessions
History
Date
Time
Result
Not Attempted Yet
Tough and Tricky questions: Geometry.
A rectangular solid box is x inches long, y inches wide and z inches tall, where x, y, and z are positive integers, exactly two of which are equal. What is the total surface area of the box?
(1) One face of the box has an area of 9 square inches.
(2) One face of the box has an area of 81 square inches.
Kudos for a correct solution.
19 Nov 2014, 09:17
Kudos
Bookmarks
statement 1: insufficient
2 of the values could be 3 and 3 or 9 and 1 but we still don't know what the 3rd length is.
statement 2: insufficient
insufficient for the same reason as above
combined, we still do not know. 1 set of values that works for both statements is 3x3x27 and another is 1x9x9 both which have different surface areas.
Answer E!
2 of the values could be 3 and 3 or 9 and 1 but we still don't know what the 3rd length is.
statement 2: insufficient
insufficient for the same reason as above
combined, we still do not know. 1 set of values that works for both statements is 3x3x27 and another is 1x9x9 both which have different surface areas.
Answer E!
20 Nov 2014, 08:55
Kudos
Bookmarks
Bunuel
Official Solution:
A rectangular solid box is x inches long, y inches wide and z inches tall, where x, y, and z are positive integers, exactly two of which are equal. What is the total surface area of the box?
To answer the question, we need to know the three dimensions of the box (although we don't need to know which dimension is the length or width or height).
Statement (1): INSUFFICIENT. Since the dimensions of the box are integers, the possible dimensions of 2 of the sides are either (1, 9) or (3, 3). In the first case, the third dimension of the box must be either 1 or 9 (to make two of the dimensions the same). In the second case, the third dimension must be any positive integer other than 3 (to prevent all three dimensions from being equal). We do not know enough to get the third dimension, however.
Statement (2): INSUFFICIENT. Since the dimensions of the box are integers, the dimensions of 2 of the sides could be (1, 81), (3, 27), or (9, 9). In the first case, the third dimension of the box must be either 1 or 81; in the second case, the third dimension must be 3 or 27. In the third case, the third dimension must be any positive integer other than 9. Again, we do not know enough to get the third dimension.
Statements (1) & (2): INSUFFICIENT. Using the foregoing, we can construct two cases that satisfy all the criteria: (1, 9, 9) and (3, 3, 27). These two cases lead to different surface areas (\(9+9+9+9+81+81=198\) sq. inches and \(81+81+81+81+9+9=342\) sq. inches).
Answer: E.
