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15 Jan 2015, 07:02
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (00:58) correct
27%
(01:15)
wrong
based on 138
sessions
History
Date
Time
Result
Not Attempted Yet
Does (x + a)^2 = y^2?
(1) x = y - a
(2) x = y + a
Kudos for a correct solution.
(1) x = y - a
(2) x = y + a
Kudos for a correct solution.
17 Jan 2015, 02:54
Kudos
Bookmarks
(1) We can subtract a from both sides of the equation and square it and we get to the equation in the question stem. So statement 1 is sufficient for any values x, y and a.
(2) This statement seems to contradict the equation in the question stem, so we are inclined to conclude that the statement is sufficient to answer the question. However, because the only equation we get is \((y+2a)^2=y^2\). However, there might be values for y and a that make the equation true. If a=0, then \((y+2a)^2=y^2\). This statement is therefore not sufficient.
Answer A.
(2) This statement seems to contradict the equation in the question stem, so we are inclined to conclude that the statement is sufficient to answer the question. However, because the only equation we get is \((y+2a)^2=y^2\). However, there might be values for y and a that make the equation true. If a=0, then \((y+2a)^2=y^2\). This statement is therefore not sufficient.
Answer A.
17 Jan 2015, 03:05
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Does \((x + a)^2 = y^2\)?
(1) x = y - a
=> x=y-a
=> x-a=y
==> squaring both sides => \((x+a)^2 = y^2\) sufficient
(2) x = y + a
=> x-a=y
=> squaring both sides => \((x-a)^2 = y^2\) insufficient
Hence ans is A!
Regards
SG
(1) x = y - a
=> x=y-a
=> x-a=y
==> squaring both sides => \((x+a)^2 = y^2\) sufficient
(2) x = y + a
=> x-a=y
=> squaring both sides => \((x-a)^2 = y^2\) insufficient
Hence ans is A!
Regards
SG
