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Bunuel
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Bunuel
Is -3x^3 < -3?

(1) -3x < 3

(2) x < 0

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The correct answer is B.
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Bunuel
Is -3x^3 < -3?

(1) -3x < 3

(2) x < 0

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Is -3x^3 < -3
if x <0 then -3x^3 will become +ve
if x= 0, then -3x^3 > -3
ix x >0 then there are several cases:-
if x is >1 let's say 3^1/2, then -3*3= -9 <-3
if x is <1 let's say (1/3)^1/3 then -3*1/3=-1>-3

(1) -3x < 3
or x> -1. It can be 0, (3)^2, (1/3)^2
Not sufficient

2) x < 0
x is -ve and -3x^3 will always be +ve and hence -3x^3 > -3

B is the answer
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-3x^3<-3
3x^3>3 ==> 3x^3-3>0 ==> 3(x^3-1)>0 ==> x^3>1 ?

a) 3x+3 > 0 ==> 3(x+1)>0 ==> x>-1 (not suff)

b) suff.
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Bunuel
Is \(-3x^3 < -3\)?

\(-3x^3 < -3\\ = 3x^3 > 3\\ = x^3 > 1\)

\(\textbf{(1) } -3x < 3\)

\(-x < 1\\x > -1\)

Not sufficient. \(x^3\) may be \(>\) or \(< 1\).

\(\textbf{(2) } x < 0\)

A negative number cubed is always negative. Hence \(< 1\)

Suffficient

(B) statement 2 alone is sufficient, but statement 1 alone is not sufficient to answer the question
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