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08 Feb 2015, 01:16
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
51% (02:21) correct
49%
(02:20)
wrong
based on 47
sessions
History
Date
Time
Result
Not Attempted Yet
p>q, Is q negative?
(1) pq + q^2 is positive
(2) (p^2)(q) + (p)(q^2) is positive
(1) pq + q^2 is positive
(2) (p^2)(q) + (p)(q^2) is positive
08 Feb 2015, 12:42
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OK this is what I think.
[1] pq + q^2 is negative
As q^2 is always positive and q could be either - or +.
Then pq has to be negative and larger that q^2, so that their addition will be negative.
For pq tp be negative either q or p should be negative. NS
[2] (p^2)q + p(q^2) is positive
This means that all relationships are positive. Also, since from the second part we see that p is positive then p^2 will be positive. And since p^2 is positive, it means tat q is also positive, otherwise the first relationship would be negative and it is not. So, S.
ANS B
[1] pq + q^2 is negative
As q^2 is always positive and q could be either - or +.
Then pq has to be negative and larger that q^2, so that their addition will be negative.
For pq tp be negative either q or p should be negative. NS
[2] (p^2)q + p(q^2) is positive
This means that all relationships are positive. Also, since from the second part we see that p is positive then p^2 will be positive. And since p^2 is positive, it means tat q is also positive, otherwise the first relationship would be negative and it is not. So, S.
ANS B
09 Mar 2016, 07:52
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rajthakkar
I have doubt in OA (B)
as per (1)
consider p=2 q=1 then pq+q^2 is positive thus q is +ve
also p=0 and q=-1 then pq+q^2 is positive thus q is -ve
thus insuff.
as per (2)
(p^2)(q) + (p)(q^2)
or pq(p+q)
if p=1 and q=-2(note P>Q)
then 1*-2(1-2)---->-2(-1)---->2 which is >0 and q=-ve
but if p=2 and q=1 then also pq(p+q) is also >0
so q can be +ve or -ve
so this is also insuff.
So ans must be E
