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24 Mar 2015, 04:37
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
50% (01:54) correct
50%
(02:11)
wrong
based on 330
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are integers and xy ≠ 0, what is the value of x/y ?
(1) \(x^2 + y^2 = 2xy\)
(2) \(2x^2 + x - 2xy - y = 0\)
Kudos for a correct solution.
(1) \(x^2 + y^2 = 2xy\)
(2) \(2x^2 + x - 2xy - y = 0\)
Kudos for a correct solution.
Bunuel
(1) x^2 + y^2 = 2xy --> (X-Y)^2=0 --> X=Y ---> X/Y =1 . SUFFICIENT.
(2) 2x^2 + x - 2xy - y = 0 --> X(2X+1) -Y(2X+1)=0 --> X=-1/2 OR X=Y .
We cannot find Y when X=-1/2 so both possibilities still exist X=-1/2 OR X=Y .
X=-1/2 is invalid so X=Y is the only solution .
SUFFICIENT.
Answer D
24 Mar 2015, 20:29
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Bunuel
Lucky2783, you may want to re-read the question and reconsider your response for Statement 2
Statement 1:
x^2 -2xy + y^2 = 0
(x-y)(x-y)=0
x=y
x/y=1
Sufficient
Statement 2:
2x^2 + x - 2xy - y = 0
x(2x+1)-y(2x+1) = 0
(x-y)(2x+1) = 0
x=y or x=-1/2
x=-1/2 is not a valid solution since x and y are integers
so only one solution exists, which is x=y
Sufficient
Answer: D
thanks for pointing out. 
