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Bunuel
If the average of four numbers is 35, how many of the numbers are less than 35?

(1) None of the numbers are exactly 35

(2) Two of the numbers are exactly 33
\(\mu \left( {x,y,z,w} \right) = 35\)

\(?\,\,:\,\,\,\,\# \,\,{\rm{less}}\,\,{\rm{than}}\,\,35\)

\(\left( {1 + 2} \right)\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,\left( {x,y,z,w} \right) = \left( {35 - 2,35 - 2,35 + 2,35 + 2} \right)\,\,\,\, \Rightarrow \,\,\,? = 2 \hfill \cr \\
\,{\rm{Take}}\,\,\left( {x,y,z,w} \right) = \left( {35 - 2,35 - 2,35 - 1,35 + 5} \right)\,\,\,\, \Rightarrow \,\,\,? = 3 \hfill \cr} \right.\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\,\left( {\rm{E}} \right)\)


We follow the notations and rationale taught in the GMATH method.

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Fabio.
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Bunuel
If the average of four numbers is 35, how many of the numbers are less than 35?

(1) None of the numbers are exactly 35

(2) Two of the numbers are exactly 33

Total of the four numbers = 140

(1) We can have 1 + 2 + 3 + 134 or 34 + 34 + 34 + 38. INSUFFICIENT.

(2) We can have 1 + 33 + 33 + 73 or 33 + 33 + 37 + 37. INSUFFICIENT.

(1&2) Combined, the numbers used for statement 2 still apply. INSUFFICIENT.

Answer is E.
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