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28 May 2016, 15:08
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
49% (01:55) correct
51%
(01:58)
wrong
based on 152
sessions
History
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Time
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Not Attempted Yet
Mary has $3,60 in nickels, dimes and quarters in her purse. How many dimes does she have (in her purse)?
1) The ratio of quarters to dimes to nickels is 4:5:6.
2) Twice the number of dimes equals the number of nickels plus five times the number of quarters.
I can guess how much is a quarter, but are we suposed to know how much is a nickel and a dime?
That would be very unfair.
Cheers.
1) The ratio of quarters to dimes to nickels is 4:5:6.
2) Twice the number of dimes equals the number of nickels plus five times the number of quarters.
I can guess how much is a quarter, but are we suposed to know how much is a nickel and a dime?
That would be very unfair.
Cheers.
28 May 2016, 19:01
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EBITDA
No point in getting upset.
A Dollar has 100 cents. Quarter= 25 cents. Dime = 10 cents. Nickel = 5 cents.
Statement 1
Q:D:N = 4:5:6
4x:5x:6x
4x(0.25)+5x(0.10)+6x(0.05) = 360
x+0.5 x+0.3x = 360
1.8x = 360
x = 200
Dimes : 5x = 1000 (We dont need to calculate)
Sufficient
Statement 2
Twice the number of dimes equals the number of nickels plus five times the number of quarters.
2d = n+5q
q(0.25)+d(0.10)+n(0.05) = 360
0.05(n+5q)+0.10d = 360
0.10 d + 0.10 d = 360
d can be calculated.
Sufficient
D is the answer.
28 May 2016, 23:03
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EBITDA
Hi,
It may be unfair to expect students to know this and most likely in ACTUALS, the values will be given..
But here you do not require to know the value for statement I but yes for statement II, it is required...
let the nickels, dime and quarter be of value n,d and q AND be x,y and z in number
so xn+yd+zq = 360......
we require to know x,y and z to answer
lets see the statements--
1) The ratio of quarters to dimes to nickels is 4:5:6.
since all three are in some ratio, say commom term = t..
x = 4t...........y=5t...........z=6t...
so by substituting above we can find value of t from xn+yd+zq = 360......
and then x,y and z can be found
Suff
2) Twice the number of dimes equals the number of nickels plus five times the number of quarters.
2y=x+5z....
here we require to know nickel =.05$, dime = 0.1$ and quarter = 0.25$..
and \(xn+yd+zq = 360........ 0.05x+0.1y+025z = 360.............5x+10y+25z=36000............x+2y+5z = 7200...........\\
2y+2y=7200\)
Y can be found..
suff
