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ha15
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This is a value question. Both the statements are NS. Hence correct answer is (E)
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Bunuel
What is the value of x?

(1) |x|= -x. This implies that x is not a positive number. Any non-positive number satisfies this equation: 0, -1, -2, -3.12, ... Not sufficient.

(2) |x|^2 = x^2. This is true for any x. Not sufficient.

(1)+(2) x can be any non-positive number. Not sufficient.

Answer: E.

0 is neither positive nor negative, so won't it satisfy the first condition?
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Bunuel
What is the value of x?

(1) |x|= -x. This implies that x is not a positive number. Any non-positive number satisfies this equation: 0, -1, -2, -3.12, ... Not sufficient.

(2) |x|^2 = x^2. This is true for any x. Not sufficient.

(1)+(2) x can be any non-positive number. Not sufficient.

Answer: E.

0 is neither positive nor negative, so won't it satisfy the first condition?

The solution you quote says that for (1) x can be 0. Your question is not clear.
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Bunuel
What is the value of x?

(1) |x|= -x. This implies that x is not a positive number. Any non-positive number satisfies this equation: 0, -1, -2, -3.12, ... Not sufficient.

(2) |x|^2 = x^2. This is true for any x. Not sufficient.

(1)+(2) x can be any non-positive number. Not sufficient.

Answer: E.

0 is neither positive nor negative, so won't it satisfy the first condition?

The solution you quote says that for (1) x can be 0. Your question is not clear.

I'm sorry, I didn't see this line earlier - "Any non-positive number satisfies this equation: 0, -1, -2, -3.12, ... Not sufficient"
Really don't know how I missed it :dazed ! The solution is correct. Thanks!
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ha15
What is the value of x?

(1) |x|= -x

(2) |x|^2 = x^2

OA: E

(1) \(|x|= -x\)
It is true of all non positve integers
\(x\leq{0}\)
There is no unique value of \(x\).
So Statement \(1\) alone is insufficient.

(2) \(|x|^2 = x^2\)
It is true for any value of \(x\).
There is no unique value of \(x\).
So Statement \(2\) alone is insufficient.

Combining \((1)\) and \((2)\), we get
\(x\leq{0}\)
There is no unique value of \(x\). So combining \((1)\) and \((2)\) also is insufficient.
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