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Bunuel
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Bunuel
Is x- 2xy + y = 0?

(1) Neither x nor y is an odd integer.

(2) Neither x nor y is a prime integer.

Statement 1: x & y are not odd integers.

Means they can be anything but odd integers.

If x = 0 & y = 0 as "0" is an even integer answer to the question is YES i.e., \(x- 2xy + y = 0\)

If x = 2 & y = 0, answer to the question is NO i.e., \(x- 2xy + y\neq {0}\)

Not sufficient. (Fractions can also be tried)

Statement 2:

Again we can try x & y = 0 as "0" is not prime and answer to the question is YES. \(x- 2xy + y = 0\)

Try x = 1 & y = 0 , answer to the question is NO. \(x- 2xy + y\neq {0}\)

Not Sufficient

Combining 1 & 2 "x & y are neither prime nor odd"

If x = 0 & y = 0 as "0" is an even integer answer to the question is YES i.e., \(x- 2xy + y = 0\)

x = 4 & y = 4, answer to the question is NO. \(x- 2xy + y\neq {0}\)

IMO (E)
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Bunuel
Is x- 2xy + y = 0?

(1) Neither x nor y is an odd integer.

(2) Neither x nor y is a prime integer.

We don't have any information in the question stem about x and y.

Stat 1: x and y can be even, prime,irrational or rational etc...Insufficient.

Stat 2: x and y can be odd,even,irrational etc...insufficient.

Both : We still don't have clear cut information.

IMO option E.

I believe answer should be A.

Statement 1 : Whatever the value of x and y be except 1, I believe we will never get a 0 for the given equation. Be it a even, prime, rational, irrational, etc.

Statement 2 : This could mean x = y = 1 is also valid. Hence, We may get 0 here.

For statement 1:

x=y=0 will also give a Yes

I think answer is E


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Bunuel
Is x- 2xy + y = 0?

(1) Neither x nor y is an odd integer.

(2) Neither x nor y is a prime integer.

We don't have any information in the question stem about x and y.

Stat 1: x and y can be even, prime,irrational or rational etc...Insufficient.

Stat 2: x and y can be odd,even,irrational etc...insufficient.

Both : We still don't have clear cut information.

IMO option E.

I believe answer should be A.

Statement 1 : Whatever the value of x and y be except 1, I believe we will never get a 0 for the given equation. Be it a even, prime, rational, irrational, etc.

Statement 2 : This could mean x = y = 1 is also valid. Hence, We may get 0 here.

0 is an even integer...then A is incorrect..
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