Last visit was: 26 Apr 2026, 08:53 It is currently 26 Apr 2026, 08:53
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
20,890
 [9]
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,890
 [9]
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
20,890
 [2]
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,890
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
prashantrchawla
Joined: 02 Nov 2013
Last visit: 10 Feb 2017
Posts: 58
Own Kudos:
Given Kudos: 10
Location: India
Posts: 58
Kudos: 31
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,890
Kudos
Add Kudos
Bookmarks
Bookmark this Post
prashantrchawla
Here is how I attempted the question,
Unit digit of 556^17n+339^(5m+15n) and both m and n are positive integer.
Option 1: 4m+12n=360 can be made short as m+3n=90
Taking different values of m and n and need to ensure that both are multiples of 3.
m n
3 29
6 28
.
.
30 20 and so on...
We know that unit digit of any number with unit digit 6 will always be 6. ---- Rule 1
Even power of number with unit digit 9 will give number with unit digit 1 and odd power will give 9--- rule 2

Coming to equation 556^17n+339^(5m+15n). Putting value of m and n from above values
When m = 3 and n = 29,
556^17n+339^(5m+15n) = 556^493+339^450 = 6+1 = 7 as unit digit.
When m = 6 and n = 28
556^17n+339^(5m+15n) = 556^476+339^450 = 6+1 = 7 as unit digit
For all the value of m and n the equation gives unit digit as 7.................... Sufficient

Option 2: n is the smallest 2-digit positive integer divisible by 5
In this case, n should be 10 as the smallest 2 digit positive integer divisible by 5. i.e. n = 10
In this case m value is not known, either even or odd... Not sufficient.

Answer is A. ...

Hi Prashant,

Good job. You've answered this question correctly. But the method followed by you includes multiple redundant steps. Let me give you certain clues on how to get to the answer with less effort.

Do a thorough question statement analysis to draw as many inferences as possible from the question. Try to find the answer to this question - "What do we need to get a unique answer to this question?". You can use the Rule 1 and 2 mentioned by you to arrive at the answer to the last question. Once you do so then analyse each of the statement (1) and (2) independently to solve the question.

On doing so, you will realize that you don't need to find values of m and n, and substitute them in the given expression to conclude that Statement (1) is sufficient. We will explain the same in our detailed solution, which will be posted soon.

Regards,
Saquib
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,890
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The official solution to the above question has been posted. Please go through the solution and check if you followed the same approach to solve the question.

In case of any queries, feel free to post your doubt here.
User avatar
fskilnik
Joined: 12 Oct 2010
Last visit: 03 Jan 2025
Posts: 883
Own Kudos:
Given Kudos: 57
Status:GMATH founder
Expert
Expert reply
Posts: 883
Kudos: 1,889
Kudos
Add Kudos
Bookmarks
Bookmark this Post
EgmatQuantExpert


Find the units digit of \(556^{17n} + 339^{5m+15n}\), where m and n are positive integers.

    (1) \(4m+12n = 360\)
    (2) n is the smallest 2-digit positive integer divisible by 5

\(\left\langle M \right\rangle \,\, = \,\,{\rm{units}}\,\,{\rm{digit}}\,\,{\rm{of}}\,\,M\)

\(\left\langle {{{556}^n}} \right\rangle = \left\langle {{6^n}} \right\rangle = 6\,\,,\,\,\forall n \ge 1\,\,{\mathop{\rm int}}\)

\(\left\langle {{{339}^k}} \right\rangle = \left\langle {{9^k}} \right\rangle = \left\{ \matrix{\\
\,\,9\,\,,\,\,\forall k \ge 1\,\,{\rm{odd}} \hfill \cr \\
\,\,1\,\,,\,\,\forall k \ge 2\,\,{\rm{even}} \hfill \cr} \right.\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left\langle {{{339}^{5\left( {m + 3n} \right)}}} \right\rangle = \left\{ \matrix{\\
\,\,9\,\,,\,\,\forall \,m + 3n\,\, \ge \,\,5\,\,{\rm{odd}} \hfill \cr \\
\,\,1\,\,,\,\,\forall \,m + 3n\,\, \ge \,\,4\,\,{\rm{even}} \hfill \cr} \right.\,\,\,\,\,\,\,\,\,\,\left( {m,n\,\, \ge 1\,\,{\rm{ints}}} \right)\)

\(\left\langle {{{556}^{17n}} + {{339}^{5\left( {m + 3n} \right)}}} \right\rangle \,\,\, = \,\,\,\left\{ \matrix{\\
\,\,\left\langle {6 + 9} \right\rangle = 5\,\,,\,\,\forall \,m + 3n\,\, \ge \,\,5\,\,{\rm{odd}} \hfill \cr \\
\,\,\left\langle {6 + 1} \right\rangle = 7\,\,\,,\,\,\forall \,m + 3n\,\, \ge \,\,4\,\,{\rm{even}} \hfill \cr} \right.\,\,\,\,\,\,\,\,\,\,\left( {m,n\,\, \ge 1\,\,{\rm{ints}}} \right)\)


\(?\,\, = \left\langle {{{556}^{17n}} + {{339}^{5\left( {m + 3n} \right)}}} \right\rangle \,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\,\,?\,\,\,:\,\,\,m + 3n\,\,\,{\rm{odd/even}}\,\,\,\,\,\,\,\,\,\,\left[ {\,m,n\,\, \ge 1\,\,{\rm{ints}}\,} \right]\,\)


\(\left( 1 \right)\,\,\,4m + 12n = 360\,\,\,\,\, \Rightarrow \,\,\,\,m + 3n = 90\,\,\left( {{\rm{even}}} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\rm{SUFF}}.\,\,\,\,\,\,\,\left( {? = 7} \right)\)


\(\left( 2 \right)\,\,n = 10\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,m = 1\,\,\,\, \Rightarrow \,\,\,\,m + 3n = 31\,\,\left( {{\rm{odd}}} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = 5\,\, \hfill \cr \\
\,{\rm{Take}}\,\,m = 2\,\,\,\, \Rightarrow \,\,\,\,m + 3n = 32\,\,\left( {{\rm{even}}} \right)\,\,\,\, \Rightarrow \,\,\,\,\,? = 7\,\, \hfill \cr} \right.\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,988
Own Kudos:
Posts: 38,988
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109837 posts
498 posts
212 posts