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Solution:



Steps 1 & 2: Understand Question and Draw Inferences

Given:

    • Isosceles ΔABC
      o AB = AC
      o So, perpendicular AD will bisect side BC.
      o If we assume ∠ ABC to be \(x^o\), the different ∠s in the figure can be represented as below:



To find: Perimeter of ΔABC
    • =AB + BC + CA
    • = 2AB + BC
So, to find the perimeter, we need to know AC and BC
Knowing the ∠s may help us (because we may then employ trigonometric ratios)

Step 3: Analyze Statement 1 independently

(1) ∠BAD = 2∠ACD
    90°- x° = 2x°
    ⇒ 3x° = 90°
    ⇒ x° = 30°
But we don’t know the magnitude of any side of the triangle. So, we cannot yet use trigonometric ratios to find the sides of the triangle.

Not sufficient.

Step 4: Analyze Statement 2 independently

(2) The perimeter of triangle ADB is 15 + 5√3

\(\begin{array}{l}\mathrm{AB}\;+\;\mathrm{BD}\;+\;\mathrm{AD}\;=\;15\;+\;5\surd3\\\Rightarrow\mathrm{AB}\;+\frac{\mathrm{BC}}2\;+\;\mathrm{AD}\;=\;15\;+\;5\sqrt3\\\Rightarrow2\mathrm{AB}+\mathrm{BC}=30+10\sqrt3-2\mathrm{AD}\end{array}\)
    The value of 2AB + BC depends on the value of AD.
    Since we do not know the value of AD, we cannot find the required value

Not sufficient.

Step 5: Analyze Both Statements Together (if needed)

    • From Statement 1:



    • From Statement 2: \(2\mathrm{AB}+\mathrm{BC}=30+10\sqrt3-2\mathrm{AD}\) . . . (I)
    • In right ΔADB
    \(\frac{\mathrm{AD}}{\mathrm{AB}}=\sin⁡30^\circ=\frac12\)
    ⇒ \(\mathrm{AD}=\frac{\mathrm{AB}}2\) . . . (II)

    \(\begin{array}{l}\frac{\mathrm{BD}}{\mathrm{AB}}=\cos⁡30^\circ=\frac{\sqrt3}2\\\Rightarrow\mathrm{BD}=\frac{\mathrm{BC}}2=\frac{(\sqrt3)\mathrm{AB}}2\\\Rightarrow\mathrm{BC}=(\sqrt3)\mathrm{AB}\end{array}\)
    • So, \(2\mathrm{AB}+(\sqrt3)\mathrm{AB}=30+10\sqrt3-2\ast\frac{\mathrm{AB}}2\)
      o A linear equation in AB. So, we’ll get a unique value of AB
    • Using Equation II, a unique value of AD will be obtained
    • Using Equation I, the value of 2AB + BC will be obtained
Sufficient.

Answer: Option C

Thanks,
Saquib
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