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Bunuel
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Best way is to think of one negative integer, that ways A and B are ruled and so is C. E is clearly the answer.

Say U + V has to be 350. It can be either 150 + 200 (answers the Q) OR -100 + 450 (does not answer the Q)

St 2 says none of the integers is equal to 100. Well we can always have 99 and 101 (answering the Q) and we can also have 150 + rest of the integers as less than 100 (not answering the Q).

Merging the two statements, nothing new will be obtained. E is the answer.
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Bunuel
The average (arithmetic mean) of integers r, s, t, u, and v is 100. Are exactly two of the integers greater than 100?

(1) Three of the integers are less than 50.
(2) None of the integers is equal to 100.
See here i done it we give that mean of R,S,T,U and V is 100.
We need=Are exactly two of the integers greater than 100?
S.1)Three of the integers are less than 50:-
So here i assume that R=49 S=48 T=47 AND
Now we see R+S+T+U+V/5=100
49+48+47+U+=500
144+U+V=500
U+V=500-144
U+V= 356
Here we can tell that U+V can be greater than 100 but listen there has chance that U can be 1 and V can be 355 so its insufficinet

S.2) It is telling that Non of the integers is equal to zero
Actually here i assume that none of than zero means all are less than 0 so its insufficient

ANS:-E
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