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chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?
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yes ,
there seems a typo in OA.

u1983
chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?
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gmatbusters
What is your doubt?

OA is correct.

u1983
chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?


What if .... if one of the integers is 0 ?

0 is interger , but neither +ve nor -ve..... :-( now, what the next blunder I am up to :-(
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I think C is correct:
A. 1 number is negative, --> a: negative
Case 1: a=-2, b=0, c=1, d=2--> abcd<0
Case 2: a=-2, b=1, c=2, d=3--> abcd>0
Insufficient.
B. insufficient.
a + b: eliminate case 1 --> sufficient.
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gmatbusters
What is your doubt?

OA is correct.

u1983
chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?




Hi gmatbusters
Is saying what is the probablilty of abcd>0 the same as Is abcd>0?

If yes what is the difference? and how would we calculate the exact probability?

If not?
Then the question is asking Q.abcd>0?

Statement 1:
Only one term is negative.
has to be D=-ve
A,B,C can be positive or 0
Case 1: Ab positive c=0 d=-ive . Ans 0
SO abcd is not positive.

Case 2: Abc are positive
so abcd will be negative.
so abcd is not positive.

IN both cases the answer is NO.
Hence I marked this statement as suuficient.

Can you tell me where I am going wrong?
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u1983
chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?


Sorry, there was a typo ... edited it.
Thanks
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nitesh50


u1983
chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?




Hi gmatbusters
Is saying what is the probablilty of abcd>0 the same as Is abcd>0?

If yes what is the difference? and how would we calculate the exact probability?

If not?
Then the question is asking Q.abcd>0?

Statement 1:
Only one term is negative.
has to be D=-ve
A,B,C can be positive or 0
Case 1: Ab positive c=0 d=-ive . Ans 0
SO abcd is not positive.

Case 2: Abc are positive
so abcd will be negative.
so abcd is not positive.

IN both cases the answer is NO.
Hence I marked this statement as suuficient.

Can you tell me where I am going wrong?

Hi..

for answering a probability question we should be aware of the properties of the number in question.
here we have variables and we should know about them. here it literally becomes a question Is abcd positive..
Statement II will not give an answer,,..
since bc is positive, a is surely positive so abc is positive but we still do not know about d, so insuff.
if d is positive probability is 1, if not probability is 0
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Statement 1
Only one number is negative. Implies the remaining three are greater than zero or two of them are greater than zero and one of them is zero.
In either case the probability of abcd being positive is zero.
Sufficient

Statement 2
bc is positive. Implies either both 'b' and 'c' are positive or both are negative.
If 'b' and 'c' both are positive, then 'a' must also be positive. So 'd' can be zero or negative. Probability of abcd being positive in both cases is zero.
If 'b' and 'c' are both negative, then 'd' must be negative. But, 'a' can be negative or zero or positive. Hence probability here can't be determined.
Therefore, Insufficient

Answer - A

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chetan2u
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chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question


Hello Mods ( chetan2u , gmatbusters , amanvermagmat , Bunuel , VeritasKarishma )....... could we please check the OA again ?


Sorry, there was a typo ... edited it.
Thanks

Np.

But still I would have got the ans wrong................ again I mixed up DS yes/no VS value Q ....... Thanks a bunch chetan2u .....completely fine ......... Thanks again :-)
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chetan2u
If \(a>b>c>d\) and a,b,c and d are integers, what is the probability that product \(abcd\) is positive?

(1) Only one number is on left side of 0 on the number line.
(2) \(bc\) is positive


NEW question

Quite interesting!

We know one number is on the left side of zero so it means we have 1 negative.

- * 3 other options (whether they’re all or all 0)

We get an answer of NO. Because 0 is neither positive nor negative. So it is not positive.

If - * + then we have an answer of NO it is negative not positive.


For statement 2)

BC is positive is not necessarily indicative of anything. It only means they are the same sign either both positive or both negative

b = 3 and c = 2

D could -ve or +ve so we have two different answers

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