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Bunuel
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(2) Say we had 10 nickels. Then this was increased to 11 and we would have 22 dimes in the bag.
This is enough to calculate the ratio!
If we try different numbers of nickles, we can SEE that we will always have 2*(n+1) dimes in the bag
Sufficient!

If that were true -- if any time you had n nickels, you had 2(n+1) dimes -- then the Statement would not be sufficient. The question asks for the ratio of nickels to dimes, and the ratio n/2(n+1) is different for different values of n.

It is not true that we have 2(n+1) dimes, except when n is exactly equal to 10. Here we know if we multiply n by 1.1 (increase it by 10%), we get 1/2 the number of dimes. So

1.1n = d/2
n/d = 1/2.2 = 5/11

so Statement 2 gives us the ratio we need. Since Statement 1 clearly does not, the answer is B.
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DavidTutorexamPAL

(2) Say we had 10 nickels. Then this was increased to 11 and we would have 22 dimes in the bag.
This is enough to calculate the ratio!
If we try different numbers of nickles, we can SEE that we will always have 2*(n+1) dimes in the bag
Sufficient!

If that were true -- if any time you had n nickels, you had 2(n+1) dimes -- then the Statement would not be sufficient. The question asks for the ratio of nickels to dimes, and the ratio n/2(n+1) is different for different values of n.

It is not true that we have 2(n+1) dimes, except when n is exactly equal to 10. Here we know if we multiply n by 1.1 (increase it by 10%), we get 1/2 the number of dimes. So

1.1n = d/2
n/d = 1/2.2 = 5/11

so Statement 2 gives us the ratio we need. Since Statement 1 clearly does not, the answer is B.

Thanks for pointing out the typo! It shouldn't be "+1" but "+10%" of course, i.e. +0.1n. Which reduces to what you wrote. Fixed.
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