Bunuel
How many times does Mary get paid in a certain year X ?
(1) Mary is paid every Friday.
(2) The year X is a leap year.
Every leap year has 366 days. Now, if we divide 366 by 7, and write it in the form 'Dividend = Divisor*Quotient + Remainder' then we get:
366 = 7*52 + 2
This means all 7 days (Monday to Sunday) appear at least 52 times in a leap year, but there are 2 days which will appear one more time. These two days will obviously be the first two days of the year. So if a leap year has started with Monday (meaning if 1st January is Monday), then the first two days (Monday and Tuesday) will appear 53 times in that year, rest five days (Wednesday to Sunday) will appear 52 times.
Statement 1Mary is paid every Friday, but we dont know how many Fridays are there in that year, we dont know whether its a normal year or a leap year.
Not sufficient.
Statement 2No information about how often Mary gets paid.
Not sufficient.
Combining the two statements, Mary is paid every Friday, and this is a leap year. Now, if this year starts with Thursday or Friday, then Friday will appear 53 times this year (first two days will be 53 times, as explained above). But if this year starts with any other day then Friday will appear 52 times only.
so Mary is paid either 52 or 53 times,
not sufficient.
Hence
E answer