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03 Apr 2018, 21:16
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
75% (01:08) correct
25%
(01:44)
wrong
based on 180
sessions
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If x ≠ 0, what is the value of k?
(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)
(2) \(\frac{k}{x} = 2\)
(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)
(2) \(\frac{k}{x} = 2\)
03 Apr 2018, 21:54
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Bunuel
From1:since x ≠ 0.
dividing x from both side
\(\frac{3}{4} + \frac{k}{3} = \frac{1}{}\)
one variable one equation sufficient.
from2:
two variable one equation ,insufficient.
hence A
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04 Apr 2018, 15:19
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Bunuel
(1) \(\frac{3}{4x} + \frac{k}{3x} = \frac{1}{x}\)
As x ≠ 0 &and can't be zero actually), then we can cancel out x
\(\frac{3}{4} + \frac{k}{3} =1\)
We have an equation with 1 unknown (K)
Sufficient
(2) \(\frac{k}{x} = 2\)
This a ratio so we can't determine value of k
insufficient
Answer: A
