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Bunuel
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What is the value of \(\frac{A}{B}\) if \(\frac{A}{B} = \frac{C}{D} = \frac{E}{F} = \frac{G}{H}\) ?


(1) \(\frac{E}{F} = 3\)

(2) \(\frac{C}{G} = 2\)

As it isn't entirely clear where to start, we'll look to the statements first.
This is an Alternative approach.

(1) Since A/B = E/F, this tells us exactly what we need!
Sufficient.

(2) If we try manipulating the given stem to get C/G, we'd need to divide all the equations by G and multiply them all by D, giving AD/BG = C/G. This is insufficient to determine the value of A/B. Another way to see this is to pick numbers: say C = 2 and G = 1. If D = 2 then A/B = 1 but if D = 1 then A/B = 2.
Insufficient.

(A) is our answer.

C/D=G/H (given)
can we write it as C/G=D/H

Yes, we can!
But - notice that neither C/G nor D/H are equal to A/B, This is because 'manipulating the equations' means dividing by G and multiplying by D which would transform A/B into AD/BG
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