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Bunuel
In a carnival game, players try to toss marbles in to a milk jug. One point is awarded when a marble hits the jug without going in, two points are awarded when a marble goes into the jug, and no points are awarded when a marble misses the jug completely. If Maurice scored m points while playing the game, is m odd?

(1) Exactly three of Maurice's marbles hit the jug without going in.

(2) Exactly five of Maurice's marbles went into the jug.

when a marble hits the jug without going in, X = 1 Point
when a marble goes into the jug, Y = 2 Points

Statement 1:
3 times X = 3 Points, which is Odd. Sufficient
Statement 2:
5 times Y = 10 Points, which is even. Sufficient Here we don't know how marbles hits the jug without going in.

Case 1) If marbles hits the jug without going in = 1

10+1 =11 Odd

Case 2) If marbles hits the jug without going in = 2

10+2=12 Even

Hence A not D

Correct me if I'm wrong :-)
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NandishSS

Case 1) If marbles hits the jug without going in = 1

10+1 =11 Odd

Case 2) If marbles hits the jug without going in = 2

10+2=12 Even

Hence A not D

Correct me if I'm wrong :-)[/quote]

Question has mentioned only two conditions. So I don't think assuming a case, in which there are any points if marble hits the jug and goes in would be correct.
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Akash720

Statement 1:
3 times X = 3 Points, which is Odd. Sufficient
Statement 2:
5 times Y = 10 Points, which is even. Sufficient

Hence D
Akash720
Statement 1) and 2) can never have two different values i.e, even and odd in your case, and still suffice the condition in question individually.
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sudarshan22
Akash720

Statement 1:
3 times X = 3 Points, which is Odd. Sufficient
Statement 2:
5 times Y = 10 Points, which is even. Sufficient

Hence D
Akash720
Statement 1) and 2) can never have two different values i.e, even and odd in your case, and still suffice the condition in question individually.

sudarshan22
Oh okay! So how can we solve Statement 2?

Assuming two cases as NandishSS mentioned. Is it correct?
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Akash720

Oh okay! So how can we solve Statement 2?

Assuming two cases as NandishSS mentioned. Is it correct?
That should do, his reasoning is better.

St 1) Score = Odd
Therefore either score or no score for remaining hits, the o/p will still be odd, i.e O + E = O
Sufficient

St 2) Score = Even
But you have no detail on remaining hits and miss, could be even or be odd.
Insufficient

Hence, A.

But, please correct me if I am wrong ehh :P
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Question stem:
2A+B=M

A is no of toss when marble get into jug
B is no of toss when marble just touch the jug without going into it

Statement 1
B = 3
so e+o= o
Sufficient.

Statement 2
A= 5
e+o= o
e+e= e
Not sufficient.

A is answer.
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Bunuel
In a carnival game, players try to toss marbles in to a milk jug. One point is awarded when a marble hits the jug without going in, two points are awarded when a marble goes into the jug, and no points are awarded when a marble misses the jug completely. If Maurice scored m points while playing the game, is m odd?

(1) Exactly three of Maurice's marbles hit the jug without going in.

(2) Exactly five of Maurice's marbles went into the jug.

#1
exactly three hit jug = 3 points ; odd so now any hit if it goes inside will give even points odd+even ; odd
sufficient
#2
Exactly five of Maurice's marbles went into the jug
so we have even value but what if 1 hits jug so total will be odd
insufficient
IMO A
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