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Bunuel
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Bunuel
If x and y are positive integers, is \((\frac{x}{y})^z > 1\) ?


(1) x - y = -5

(2) z ≠ 0
Here is my approach.

(1) x - y = -5 --> x < y --> \(\frac{x}{y}\) < 1 . No info about z --> not sufficient.
(Number plugging: Let \(\frac{x}{y}\) = \(\frac{1}{6}\). If \(z = 1\) --> Yes, If \(z=-1\) --> No)

(2) z ≠ 0 --> No info about x, y --> not sufficient.

(1) + (2) We still have two different answers --> not sufficient.

Answer E.
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