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14 Mar 2019, 07:20
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:22) correct
23%
(01:25)
wrong
based on 52
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GMATH practice exercise (Quant Class 14)
What is the selling price (in dollars) of the HK11B-connector (a specific electronic widget) in Mrs. Tao´s store?
(1) In Mrs. Tao´s store, the difference between the selling price of the HK11B-connector and the cost of this electronic widget is 500 dollars.
(2) If Mrs. Tao agrees on a 10% discount over the selling price of the HK11B-connector, her profit would be 20% over the cost of this electronic widget.
What is the selling price (in dollars) of the HK11B-connector (a specific electronic widget) in Mrs. Tao´s store?
(1) In Mrs. Tao´s store, the difference between the selling price of the HK11B-connector and the cost of this electronic widget is 500 dollars.
(2) If Mrs. Tao agrees on a 10% discount over the selling price of the HK11B-connector, her profit would be 20% over the cost of this electronic widget.
14 Mar 2019, 07:33
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Statement 1: \(Profit = 500 = P - C\). Not sufficient to compute \(P\).
Statement 2: \(0.2C = 0.9P - C\)
\(1.2C = 0.9P\). Still not sufficient.
Together, we can solve a two-linear equation system to compute \(P\) and \(C\). Hence, C is the correct answer.
Statement 2: \(0.2C = 0.9P - C\)
\(1.2C = 0.9P\). Still not sufficient.
Together, we can solve a two-linear equation system to compute \(P\) and \(C\). Hence, C is the correct answer.
14 Mar 2019, 13:44
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fskilnik
\(s,c\,\,\, \to \,\,\,\,\left[ {{\rm{dollars}}} \right]\)
\(? = s\)
\(\left( 1 \right)\,\,\,s - c = 500\,\,\,::\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,\left( {s,c} \right) = \left( {600,100} \right)\,\,\,\, \Rightarrow \,\,\,? = 600\,\, \hfill \cr \\
\,{\rm{Take}}\,\,\left( {s,c} \right) = \left( {700,200} \right)\,\,\,\, \Rightarrow \,\,\,? = 700\,\, \hfill \cr} \right.\)
\(\left( 2 \right)\,\,{9 \over {10}}s = {{12} \over {10}}c\,\,\,\,\,\mathop \Rightarrow \limits^{c\, \ne \,0} \,\,\,\,\,{s \over c} = {4 \over 3}\,\,\,\,\,\,::\,\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,\left( {s,c} \right) = \left( {4,3} \right)\,\,\,\, \Rightarrow \,\,\,? = 4\,\, \hfill \cr \\
\,{\rm{Take}}\,\,\left( {s,c} \right) = \left( {40,30} \right)\,\,\,\, \Rightarrow \,\,\,? = 40\,\, \hfill \cr} \right.\,\,\)
\(\left( {1 + 2} \right)\,\,\,::\,\,\,\left\{ \matrix{\\
\,\,s - c = 500\,\,\,\left( {\rm{I}} \right)\,\,\,\, \hfill \cr \\
\,\left( {s,c} \right) = \left( {4k,3k} \right)\,\,\,\left( {{\rm{II}}} \right)\,\,\,\, \hfill \cr} \right.\left( {k > 0} \right)\,\,\,\,\,\mathop \Rightarrow \limits^{\left( {{\rm{II}}} \right)\,\,{\rm{in}}\,\,\left( {\rm{I}} \right)} \,\,\,\,\,\,k\,\,{\rm{unique}}\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = 4k\,\,\,{\rm{unique}}\)
The correct answer is (C).
We follow the notations and rationale taught in the GMATH method.
Regards,
Fabio.
