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Bunuel
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IMO D

Statement 1
Take set : 1,3,5,7,9
Mean = 1+3+5+7+9/5 =25/5= 5
Median = 5

Statement 2

Take set : 1,2,3
Mean = 1+2+3/3 = 6/3 = 2

We can take one more set to confirm

Take set : 1,2,3,4,5
Mean = 1+2+3+4+5/5 = 15/5 = 3
Median = 3

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AmanMatta
#2 says set has odd no of values ; what if set has 1,11,13 ; will your statement still hold true then??

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IMO D

Statement 1
Take set : 1,3,5,7,9
Mean = 1+3+5+7+9/5 =25/5= 5
Median = 5

Statement 2

Take set : 1,2,3
Mean = 1+2+3/3 = 6/3 = 2

We can take one more set to confirm

Take set : 1,2,3,4,5
Mean = 1+2+3+4+5/5 = 15/5 = 3
Median = 3

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Set contains positive integers , find Is Mean = median ?

1) The numbers in Set Q are consecutive and odd.==> Sufficient
s = { 1,3,5 } ==> mean = 3 , Median = 3
s = { 1,3,5,6}==> Mean == Median = \(\frac{{3+5}}{2}\)


(2) Set Q contains an odd number of numbers. ==> In sufficient

It is not given that numbers are consecutive , would be some random numbers Ex: { 4,6,10,15,20}

Option is A

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