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805+ (Hard)|   Sequences|      
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Bunuel
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What is the mean (average) of the numbers in the series if each number 12 Jul 2019, 01:30
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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95% (hard)

Question Stats:

36% (01:53) correct 64% (01:47) wrong based on 154 sessions

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What is the mean (average) of the numbers in the sequence if each number in the series is different from the others?

(1) The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains and no element repeats in the sequence.
(2) The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.
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A
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What is the mean (average) of the numbers in the series if each number Updated on: 12 Jul 2019, 13:49
Originally posted by Archit3110 on 12 Jul 2019, 10:44.
Last edited by Archit3110 on 12 Jul 2019, 13:49, edited 1 time in total.
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Bunuel
What is the mean (average) of the numbers in the sequence if each number in the series is different from the others?

(1) The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains and no element repeats in the sequence.
(2) The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.
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#1
no can be 103,108,123,128 ... so on sufficient
#2

Insufficient
IMO A
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What is the mean (average) of the numbers in the series if each number 12 Jul 2019, 13:23
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Went for A as the sequence does not talk about repetitions in B.
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What is the mean (average) of the numbers in the series if each number 09 Feb 2020, 23:19
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Bunuel
What is the mean (average) of the numbers in the sequence if each number in the series is different from the others?

(1) The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains and no element repeats in the sequence.
(2) The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.
Show more

Solution


Step 1: Analyse Question Stem


• Each Element of the sequence is different.
We need to find the average of the numbers in the sequence

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE


Statement 1: The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains, and no element repeats in the sequence
    • According to this statement: Each element of the sequence is distinct and
      o All the elements of the sequence can be represented by \(5k+3\), where \( 99 < 5k+3 < 1000 \)and k is a positive integer.
         Or, \(\frac{(99-3)}{5} < k < \frac{(1000-3)}{5}\)
         Or, \(19.2 < k < 199.4 \)
         Thus, \(20 ≤ k ≤ 199\)
We have found range of k; hence we determine each element of the sequence and can find the average or mean of the sequence.
Hence, statement 1 is sufficient and we can eliminate answer options B, C and E.
Statement 2: The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.
    • According to this statement:
      o Sequence contains all the numbers which are in the form of \(5k+3\), where \(99 < 5k+3 < 1000\) and k is a positive integer.
    • However, we don’t know if there are any other elements in the sequence or not.
Hence, statement 2 is NOT sufficient.
Thus, the correct answer is Option A.
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What is the mean (average) of the numbers in the series if each number 02 Aug 2020, 08:03
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Bunuel
What is the mean (average) of the numbers in the sequence if each number in the series is different from the others?

(1) The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains and no element repeats in the sequence.
(2) The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.

Solution


Step 1: Analyse Question Stem


• Each Element of the sequence is different.
We need to find the average of the numbers in the sequence

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE


Statement 1: The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains, and no element repeats in the sequence
    • According to this statement: Each element of the sequence is distinct and
      o All the elements of the sequence can be represented by \(5k+3\), where \( 99 < 5k+3 < 1000 \)and k is a positive integer.
         Or, \(\frac{(99-3)}{5} < k < \frac{(1000-3)}{5}\)
         Or, \(19.2 < k < 199.4 \)
         Thus, \(20 ≤ k ≤ 199\)
We have found range of k; hence we determine each element of the sequence and can find the average or mean of the sequence.
Hence, statement 1 is sufficient and we can eliminate answer options B, C and E.
Statement 2: The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.
    • According to this statement:
      o Sequence contains all the numbers which are in the form of \(5k+3\), where \(99 < 5k+3 < 1000\) and k is a positive integer.
    • However, we don’t know if there are any other elements in the sequence or not.
Hence, statement 2 is NOT sufficient.
Thus, the correct answer is Option A.
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Are you saying answer is option A just because of the missing are all the elements that the sequence contains in statement 2, which is there in statement 1

(1) The 3-digit numbers that have a remainder of 3 when divided by 5 are all the elements that the sequence contains and no element repeats in the sequence.
(2) The sequence consists of all the 3-digit numbers that have a remainder of 3 when divided by 5.
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What is the mean (average) of the numbers in the series if each number 13 Apr 2026, 11:27
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In Statement B , It says consists of, Does not consist of means (all) , Just trying to understand if consist of and contains should be interpreted in the same manner?
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