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(1) X is an integer
N can take any value integer or non - integer.
a. N is an integer → \(X^N\) is an integer. Example X = 2, N = 1, 2, 3 and so on. YES
b. N is non – integer → \(X^N\) is non - integer. Example X = 2, N = 0.1, 0.2, 0.5 and so on. NO
INSUFFICIENT.

(2) N is an integer
X can take any value integer or non - integer.
a. X is an integer → \(X^N\) is an integer. Example N = 2, X = 1, 2, 3 and so on. YES
b. X is non – integer → \(X^N\) is non integer. Example N = 2, X = 0.1, 0.2, 0.5 and so on. NO
INSUFFICIENT.

Together 1) and 2)
Since both are integers Case ‘a’ of both statements suffices YES condition.

SUFFICIENT.
Answer (C).
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#1
value of N not know insufficient as -ve integer value of N will be fraction
insufficient
#2
N is an integer ; value of X not know insufficeint
from 1&2
value of sign of x & n not know
insufficient
IMO E

Is X^N an integer?

(1) X is an integer
(2) N is an integer
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Quote:

Is \(X^N\) an integer?

(1) X is an integer
(2) N is an integer

rule: "integer" = {positive, negative or zero}

(1) X is an integer: \(X,N=(2,1):X^N=2^1=2=integer…X,N=(2,-1):X^N=2^{(-1)}=0.5=not.integer\)
(2) N is an integer: \(X,N=(2,1):X^N=2^1=2=integer…X,N=(2,-1):X^N=2^{(-1)}=0.5=not.integer\)

Answer (E)
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Analyzing the question:
Note that x does not have to be an integer for this to be sufficient. For example, we may have x = sqrt(2) and N be any even number, and this would be sufficient. Also, N = 0 is automatically sufficient if x cannot be 0.

Statement 1:
Without knowing N this is insufficient. N can be 1/2, which is square of x. There's also the possibility that N is a negative integer.

Statement 2:
x can be sqrt(2) and N=1. Insufficient.

Combined:
Still insufficient as we can let N = -1 and x be any integer greater than 1 to create a fractional result. Answer is E.
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Both statements are not sufficient as for X to the power of N to be an integer, we need X to be an integer and N to be a positive integer. From the given information, N can be either positive or negative and statement 1 is anyway not sufficient.

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Clearly statement 1,2 are not sufficient exclusively
If we consider both, for x=2, n=3 .....x^n is integer but if n=-2 then x^n is not integer
SO OA:E
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Bunuel

Competition Mode Question



Is X^N an integer?

(1) X is an integer
(2) N is an integer

Is X^N an integer?

(1) X is an integer
\(2^2\) is an integer
\(2^{-2}\) is not an integer
NOT SUFFICIENT

(2) N is an integer
\(2^2\) is an integer
\(2^{-2}\) is not an integer
NOT SUFFICIENT

Combining (1) & (2)
\(2^2\) is an integer
\(2^{-2}\) is not an integer
NOT SUFFICIENT

IMO E
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Is X^N an integer?

(1) X is an integer
N could be negative - which leads to a fraction.
(2) N is an integer
N could still be negative - which leads to a fraction.
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