Is xy divisible by 3, if xy is a 2-digit number, where x and y are single digits?
(1) x*y is divisible by 3.
(2) x is not divisible by 3.
If the sum of digits is a multiple of 3 then the number is divisible by 3.
Hence we need to identify is x + y a multiple of 3.
(1) x*y is divisible by 3
If the number is 13, it is not divisible by 3 and satisfies the condition mentioned in statement 1
If the number is 33, it is divisible by 3 and satisfies the condition mentioned in statement 1
Hence not sufficient.
(2) x is not divisible by 3,
Which means first number cant be a multiple of 3.
Hence we can take a example of,
12, which is divisible by 3 and
13, which is not divisible by 3
Again not sufficient.
If we combine both of them,
x*y is divisible by 3 and x is not a multiple of 3,
that means y has to multiple of 3
And x is not divisible by 3
So we can look at the examples..
13,16,19
23,26,29
that is the sum will not be a multiple of 3 as we add two numbers one a 3's multiple and the other isn't, it will not be a multiple of 3,(sum of the numbers has to be multiple of 3 for the number to be divisible by 3), hence the number is not a multiple of 3
So we can answer the question after combining them, that xy is not a multiple of 3.
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