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21 Sep 2019, 16:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:10) correct
27%
(02:01)
wrong
based on 1242
sessions
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Alan and Sue have each been saving one dollar a day and will continue to do so for the next month. If Sue began saving several days before Alan, in how many days from today will Alan have saved one-half as much as Sue?
(1) As of today, Alan has saved 7 dollars and Sue has saved 27 dollars.
(2) Three days from today, Alan will have saved one-third as much as Sue.
DS89302.01
(1) As of today, Alan has saved 7 dollars and Sue has saved 27 dollars.
(2) Three days from today, Alan will have saved one-third as much as Sue.
DS89302.01
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30 Sep 2019, 05:54
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Assume 'x' days from today, Alan will save 1/2 as much as Sue.
Statement 1-
\((7+x)=\frac{1}{2}(27+x)\)
x=13
Sufficient
Statement 2-
Savings by Alan, as of today= A
Savings by Sue, as of today= S
\((A+3)=\frac{1}{3}(S+3)\)
Also, \((A+x)=\frac{1}{2}(S+x)\)
We have 2 equations and 3 unknowns (A, S and x)
Insufficient
Statement 1-
\((7+x)=\frac{1}{2}(27+x)\)
x=13
Sufficient
Statement 2-
Savings by Alan, as of today= A
Savings by Sue, as of today= S
\((A+3)=\frac{1}{3}(S+3)\)
Also, \((A+x)=\frac{1}{2}(S+x)\)
We have 2 equations and 3 unknowns (A, S and x)
Insufficient
gmatt1476
General Discussion
04 Jun 2020, 01:52
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OFFICIAL EXPLANATION:
Let A be the amount Alan has saved as of today. Let S be the amount Sue had already saved when Alan started saving. Then, as of today, Sue has saved S + A dollars. Determine d, the number of days from today that Alan will have saved half as much as Sue. That is, determine d, where A + d = 62604.png(S + A + d) or, after algebraic manipulation, determine d such that d = S − A.
A) It is given that A = 7 and S = 27, so d = 20; SUFFICIENT.
B) It is given that three days from today, Alan will have saved one-third as much as Sue, from which it follows that A + 3 = 62611.png(S + A + 3) or, after algebraic manipulation, S = 2A + 6. Then, d = S − A = (2A + 6) − A = A + 6. Since the value of A can vary, the value of d cannot be determined; NOT sufficient.
The correct answer is A;
statement 1 alone is sufficient.
Let A be the amount Alan has saved as of today. Let S be the amount Sue had already saved when Alan started saving. Then, as of today, Sue has saved S + A dollars. Determine d, the number of days from today that Alan will have saved half as much as Sue. That is, determine d, where A + d = 62604.png(S + A + d) or, after algebraic manipulation, determine d such that d = S − A.
A) It is given that A = 7 and S = 27, so d = 20; SUFFICIENT.
B) It is given that three days from today, Alan will have saved one-third as much as Sue, from which it follows that A + 3 = 62611.png(S + A + 3) or, after algebraic manipulation, S = 2A + 6. Then, d = S − A = (2A + 6) − A = A + 6. Since the value of A can vary, the value of d cannot be determined; NOT sufficient.
The correct answer is A;
statement 1 alone is sufficient.
