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gmat1393
chetan2u
If \(2|x|+x^2\neq{0}\), what is the value of \( \frac{1}{2|x|+x^2}\)?
(1) \(|x|=x^2\)
(2) \(\frac{|x|}{x}>0\)


Chetan's question

\(2|x|+x^2\neq{0}\)
this implies \(x\neq{0}\)

1 => x can be -1, 0 or 1
since x cannot be 0 x can be -1 or 1
both the values give same result for \( \frac{1}{2|x|+x^2}\)

2 => \(x >=1\)

IMO, Answer is A

Hey, I am confused about how you derived this part:
1 => x can be -1, 0 or 1
since x cannot be 0 x can be -1 or 1
can you please elaborate?
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