GMATPrepNow
If x and y are integers, what is the value of \(xy\)?
\(1) \) \(-1 < –x^y < 0\)
\(2) \) \(-10 < y^x < -1\)
Given: x and y are integers Target question: What is the value of \(xy\)? Statement 1: \(-1 < –x^y < 0\)This is the same as writing: \(-1 < –(x^y) < 0\)
For now, let's just consider the fact that \(-(x^y)\) is negative.
This means \(x^y\) must be POSITIVE
This means EITHER x is positive, and y has any value OR x is negative and y is EVEN
Now let's also consider the fact that \(-1 < –(x^y) < 0\)
This means \(0 < (x^y) < 1\)
We can now conclude that x is POSITIVE, and y is some NEGATIVE integer.
Given this, here are some possible cases that satisfy statement 1:
Case a: x = 2 and y = -2. In this case, the answer to the target question is
xy = (2)(-2) = -4Case b: x = 2 and y = -3. In this case, the answer to the target question is
xy = (2)(-3) = -6Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: \(-10 < y^x < -1\)If \(y^x\) is negative, then we know that y must be NEGATIVE and x must be ODD
Given this, here are some possible cases that satisfy statement 2:
Case a: x = 1 and y = -2. In this case, the answer to the target question is
xy = (1)(-2) = -2Case b: x = 1 and y = -3. In this case, the answer to the target question is
xy = (1)(-3) = -3Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Statement 1 tells us that x is POSITIVE, and y is some NEGATIVE integer.
Statement 2 tells us that x must be ODD and y must be NEGATIVE
In order for \(-10 < y^x < -1\) and for \(-1 < –x^y < 0\), it MUST be the case that y = -2 and x = 3
The answer to the target question is
xy = (3)(-2) = -6Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer: C
Cheers,
Brent